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4 years ago

Mass is the weight of an object

Physics

1 answer:

o-na [289]4 years ago

3 0

Answer:

Mass is the amount of matter in a object.

Explanation:

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an electric current 0.75 a passes through a circuit that has a resistance of 175. according to ohm's law, what is the voltage of

Aleksandr [31]

Answer:

131.25

Explanation:

i worked it out on a diffrent sheet so its hard to explain

8 0

3 years ago

Suppose a 1300 kg car is traveling around a circular curve in a road at a constant

Scrat [10]

Answer:

F = 4212 N

Explanation:

Given that,

Mass of a car, m = 1300 kg

Speed of car on the road is 9 m/s

Radius of curve, r = 25 m

We need to find the magnitude of the unbalanced force that steers the car out of its natural straight- line path. The force is called centripetal force. It can be given by :

$F=\dfrac{mv^2}{r}\\\\F=\dfrac{1300\times 9^2}{25}\\\\F=4212\ N$

So, the force has a magnitude of 4212 N

4 0

3 years ago

Particle motion in surface waves is __________ motion.

gulaghasi [49]

<h3>Answer;</h3>

<em>B.)neither longitudinal nor transverse</em>

<h3><u>Explanation;</u></h3>

<em><u>Longitudinal waves</u></em> are waves in which the vibration of particles is parallel to the direction of the wave motion.
<em><u>Transverse waves</u></em> on the other hand are those waves in which the vibration of particles is perpendicular to the direction of the wave motion.
In <em><u>surface waves particles in the medium of transmission move in a circular motion.</u></em> Therefore, they are neither transverse waves nor longitudinal waves.

7 0

3 years ago

Read 2 more answers

the rock of 10 kg is falling near the Earth's surface.assume that g =10N/kg and the is no air resistance. what is the accelerati

Ivanshal [37]

Answer:

kya faltu sawal h repetitive g=10N/kg

5 0

3 years ago

Water enters a cylindrical tank through two pipes at rates of 250 and 100 gal/min. If the level of the water in the tank remains

tester [92]

Answer:

The total amount of water that enters the tank is:

250 gal/min + 100 gal/min = 350gal/min.

Then, if the level of the water remains constant, this means that the water leaves the tank at a rate of 350gal/min.

We know that the diameter of the pipe is 8 inches, then the area of the pipe is:

A = pi*(d/2)^2 = 3.14*(4in)^2 = 50.24in^2

now, the flow can be calculated as:

Q = v*A = (velocity*area)

if we want to write our velocity in inches per minute, then we need to write the entering flow in cubic inches:

1 gallon = 231 in^3

then:

350gal/min = (350*231) in^3/min = 80,850 in^3/min.

Then the water that leaves the tank must be the same amoun, we have:

Q = 80,850 in^3/min. = v*A = v*50.24in^2

v = (80,850in^3/min)/50.24in^2 = 1609.3 in/min.

The velocity of the flow leaving the tank is 1609.3 in/min.

3 0

4 years ago