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3 years ago

11

The tensile strength (the maximum tensile stress it can support without breaking) for a certain steel wire is 3000 MN/m2. What i

s the maximum load that can be applied to a wire with a diameter of 3.0 mm made of this steel without breaking the wire?

1 answer:

Orlov [11]3 years ago

4 0

Answer:

The correct answer is "21195 N".

Explanation:

The given values are:

Tensile strength,

= 3000 MN/m²

Diameter,

= 3.0 mm

i.e.,

= 3×10⁻³ m

Now,

The maximum load will be:

= $Tensile \ strength\times Area$

On substituting the values, we get

= $(3000\times 10^6)(\frac{\pi}{4} (3\times 10^{-3})^2)$

= $(3000\times 10^6)(\frac{3.14}{4} (3\times 10^{-3})^2)$

= $21195 \ N$

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Where T is the tension on the rope

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$M_2 a = M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2$

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making a the subject of the formula

$a = \frac{M_2 g sin \theta_2 - M_1 g sin \theta_1 - \mu_1 M_1g cos \theta - \mu_2 M_2 g cos \theta_2 }{M_1 +M_2}$

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=> $a = 0.7156 m/s^2$

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