Question

The tensile strength (the maximum tensile stress it can support without breaking) for a certain steel wire is 3000 MN/m2. What is the maximum load that can be applied to a wire with a diameter of 3.0 mm made of this steel without breaking the wire?

Answer 1

Answer:

The correct answer is "21195 N".

Explanation:

The given values are:

Tensile strength,

= 3000 MN/m²

Diameter,

= 3.0 mm

i.e.,

= 3×10⁻³ m

Now,

The maximum load will be:

=  $Tensile \ strength\times Area$

On substituting the values, we get

=  $(3000\times 10^6)(\frac{\pi}{4} (3\times 10^{-3})^2)$

=  $(3000\times 10^6)(\frac{3.14}{4} (3\times 10^{-3})^2)$

=  $21195 \ N$