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lys-0071 [83]
3 years ago
12

When playing tug of war and neither side moves, forces are...

Physics
2 answers:
Fantom [35]3 years ago
8 0

Answer:

C.Balanced... The force is balanced so neither one is being pulled harder...

Explanation:

Hope this helps!

natulia [17]3 years ago
8 0

Answer:

Balanced.

Explanation:

Both sides have equal strength. therefore the rope will not move. The Forces are Balanced! :)

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Which equation relates charge, time, and current?
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The first one

Explanation:

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people used to think that the sun moved around earth galileo proved this was wrong why is this important
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To approve to people that the Catholic Church was wrong but they threatened Galileo and he stop
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A turtle accelerates from a stop at 3m/s/s to the South for 8s. What is the turtle’s final velocity? Show your work and include
andrey2020 [161]

He's accelerating at 3 m/s² .  That means his speed is increasing by 3 m/s every second.At the end of 8 seconds, his speed is (8 x 3 m/s)  =  24 m/s .He's been moving south for the whole 8 seconds.So at the end of that time, his velocity is                          24 m/s south .

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2 years ago
All of the visible color light waves together result in____light​
Pani-rosa [81]

Answer:

White light.

Explanation:

3 0
3 years ago
The cheetah is considered the fastest running animal in the world. Cheetahs can accelerate to a speed of 21.7 m/s in 2.50 s and
viktelen [127]

Answer:

1) 64.2 mi/h

2) 3.31 seconds

3) 47.5 m

4) 5.26 seconds

Explanation:

t = Time taken = 2.5 s

u = Initial velocity = 0 m/s

v = Final velocity = 21.7 m/s

s = Displacement

a = Acceleration

1) Top speed = 28.7 m/s

1 mile = 1609.344 m

1\ m=\frac{1}{1609.344}\ miles

1 hour = 60×60 seconds

1\ s=\frac{1}{3600}\ hours

28.7\ m/s=\frac{\frac{28.7}{1609.344}}{\frac{1}{3600}}=64.2\ mi/h

Top speed of the cheetah is 64.2 mi/h

Equation of motion

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow t=\frac{21.7-0}{2.5}\\\Rightarrow a=8.68\ m/s^2

Acceleration of the cheetah is 8.68 m/s²

2)

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{28.7-0}{8.68}\\\Rightarrow t=3.31\ s

It takes a cheetah 3.31 seconds to reach its top speed.

3)

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{28.7^2-0^2}{2\times 8.68}\\\Rightarrow s=47.5\ m

It travels 47.5 m in that time

4) When s = 120 m

s=ut+\frac{1}{2}at^2\\\Rightarrow 120=0\times t+\frac{1}{2}\times 8.68\times t^2\\\Rightarrow t=\sqrt{\frac{120\times 2}{8.68}}\\\Rightarrow t=5.26\ s

The time it takes the cheetah to reach a rabbit is 120 m is 5.26 seconds

8 0
3 years ago
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