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GarryVolchara [31]
3 years ago
8

If the diameter of the black marble is 3.0cm, and bye using the formula for volume, what is a good approximation if it’s volume?

Record to the ones place
Physics
1 answer:
tia_tia [17]3 years ago
4 0

Complete question is;

If the diameter of the black marble is 3.0 cm, and by using the formula for volume, what is a good approximation of its volume?

Answer:

14 cm³

Explanation:

We will assume that this black marble has the shape of a sphere from online sources.

Now, volume of a sphere is given by;

V = (4/3)πr³

We are given diameter = 3 cm

We know that radius = diameter/2

Thus; radius = 3/2 = 1.5 cm

So, volume = (4/3)π(1.5)³

Volume ≈ 14.14 cm³

A good approximation of its volume = 14 cm³

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Answer:

The magnitude of force must you apply to hold the platform in this position = 888.89 N

Explanation:

Given that :

Workdone (W) = 80.0 J

length x = 0.180 m

The equation  for this  work done by the spring is expressed as:

W = \frac{1}{2}k_{eq}x^2

Making the spring constant k_{eq} the subject of the formula; we have:

k_{eq} = \frac{2W}{x^2}

Substituting our given values, we have:

k_{eq} = \frac{2*80}{0.180^2}

k_{eq} = 4938.27 \ N.m^{-1}

The magnitude of the force that must be apply  to the hold platform in this position is given by the formula :

F = k_{eq}x

F = 4938.27*0.180

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3 years ago
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a flashlight bulb with a potential difference of 6.0 v across it has a resistance of 8.0 how much current is the bulb filament
Andreas93 [3]

Answer:

<em>I = 0.75 Amp</em>

Explanation:

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The formula can be expressed as:

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A flashlight bulb is an example of a resistor with the specific task to emit light when it's hot enough.

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Answer:

500 J

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