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MrRissso [65]
3 years ago
10

why is the peak value of the rectified output less than the peak value of the ac input and by how much g

Engineering
1 answer:
Bumek [7]3 years ago
5 0

Answer:

The Peak value of the output voltage is less or lower than that of the peak value of the input voltage by 0.6V reason been that the voltage is tend to drop across the diode.

Explanation:

This is what we called HALF WAVE RECTIFIER in which the Peak value of the output voltage is less or lower than that of the peak value of the input voltage by 0.6V reason been that the voltage is tend to drop across the diode.

Therefore this is the formula for Half wave rectifier

Vrms = Vm/2 and Vdc

= Vm/π:

Where,

Vrms = rms value of input

Vdc = Average value of input

Vm = peak value of output

Hence, half wave rectifier is a rectifier which allows one half-cycle of an AC voltage waveform to pass which inturn block the other half-cycle which is why this type of rectifiers are often been used to help convert AC voltage to a DC voltage, because they only require a single diode to inorder to construct.

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8 0
3 years ago
A) If a given directional antenna can receive 15 times the power of an isotropic antenna, what is
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The gain of the directional antenna is calculated based on the comparison

with an hypothetical isotropic antenna.

  • a) The gain in dBi of the isotropic antenna is approximately <u>11.76 dBi</u>
  • b) The power received by the isotropic antenna is approximately <u>0.61 mW</u>

Reasons:

a) The number of times the power of the directional antenna is stronger than the  isotropic antenna, G = 15 times

The gain in dBi is given as follows;

\displaystyle G = \mathbf{10^{\dfrac{G(dBi)}{10} }}

Which gives;

\displaystyle 15 = 10^{\dfrac{G(dBi)}{10} }

\displaystyle \dfrac{G(dBi)}{10}  = \frac{ln(15)}{ln(10)}

\displaystyle G(dBi)} = 10 \times \frac{ln(15)}{ln(10)} \approx 11.76

The power gain of the isotropic antenna, G(dBi) ≈ <u>11.76 dBi</u>

b) When the gain of the directional antenna is 2.15 dBi and it received 1 mW of power, we have;

The number of times stronger the directional antenna is, is found as follows;

\displaystyle G  = 10^{\dfrac{2.15}{10} } \approx \mathbf{1.64}

The 2.15 dBi directional antenna receives the signal approximately 1.64 times stronger than the isotropic antenna, therefore;

  • \displaystyle The \ power \ received \ by \ the \ isotropic \ antenna  = \frac{1 \, mW}{1.64}  \approx \underline {0.61 \, mW}

Learn more here:

brainly.com/question/17587029

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