When you add more water to the balloon, it makes it heavier. Therefore it would weigh the balloon down ( increasing mass) and increasing the energy to plummet down. So the answer is B.
There water has a lot of salt in it, so it would be denser. People float better when the water is denser.
The correct answer is B. Calcite
Explanation:
Mohs hardness scale indicates the hardness of minerals using a scale from 1 to 10 as well as defining the objects or tools that can be used to scratch the minerals. These two features of minerals are shown in the table of the image. About this, it is shown gypsum and talc can be scratched by just a fingernail, considering minerals with a hardness of 2.5 or below can be scratched by a fingernail. In the case of calcite that has a hardness of 3, this cannot be scratched by a fingernail, but it can be scratched by a penny, which works for minerals with a hardness of 3.5 or below. Thus, the correct answer is Calcite.
Answer:
The capacitance of the capacitor is 
Explanation:
To solve this exercise it is necessary to apply the concepts related to Power and energy stored in a capacitor.
By definition we know that power is represented as

Where,
E= Energy
t = time
Solving to find the Energy we have,

Our values are:


Then,


With the energy found we can know calculate the Capacitance in a capacitor through the energy for capacitor equation, that is

Solving for C=



Therefore the capacitance of the capacitor is 
Vertical columns on the periodic table are called groups.
I hope you like this answer, please Brainliest me, and have a good day and life! :D<span />