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saul85 [17]
4 years ago
9

428. mg of an unknown protein are dissolved in enough solvent to make of solution. The osmotic pressure of this solution is meas

ured to be at . Calculate the molar mass of the protein. Round your answer to significant digits.
Chemistry
1 answer:
attashe74 [19]4 years ago
7 0

The question is incomplete, here is the complete question:

428. mg of an unknown protein are dissolved in enough solvent to make 5.00 mL of solution. The osmotic pressure of this solution is measured to be 0.0766 atm at 25.0°C. Calculate the molar mass of the protein. Round your answer to 3 significant digits

<u>Answer:</u> The molar mass of protein is 27.3\times 10^3g/mol

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

Or,

\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT

where,

\pi = osmotic pressure of the solution = 0.0766 atm

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (protein) = 428 mg = 0.428 g   (Conversion factor: 1 g = 1000 mg)

Volume of solution = 5.00 mL

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

0.0766=1\times \frac{0.428\times 1000}{\text{Molar mass of protein}\times 5}\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 298K\\\\\text{Molar mass of protein}=\frac{1\times 0.428\times 1000\times 0.0821\times 298}{0.0766\times 5}=27340.4g/mol=27.3\times 10^3g/mol

Hence, the molar mass of protein is 27.3\times 10^3g/mol

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