Answer:
Option B. 6.25 J/S
Explanation:
Data obtained from the question include:
t (time) = 2secs
F (force) = 50N
d (distance) = 0.25m
P (power) =?
The power can be obtained by using the formula P = workdone/time.
P = workdone / time
P = (50 x 0.25)/ 2
P = 6.25J/s
Answer:
To=20.44 °C
Explanation:
Given that
Velocity , v= 30 m/s
Temperature , T= 20°C
We know that specific heat capacity for air ,Cp=1.005 kJ/kg.K
By using energy conservation ,the stagnation temperature is given as

Now by putting the values in the above equation we get

To= 293.44 K
To= 293.44 - 273 °C
To=20.44 °C
Therefore the stagnation temperature will be 20.44 °C.
Answer:
Weight, W = 125 N
Explanation:
Pressure, P = 5 Pa
Area, A = 25 m²
We need to find how much must a man weigh (force) if the pressure he exerts while standing on one foot which has an area of 25 m² exerts a pressure of 5 Pa. So,
Pressure = force/area
So,

So, the weight of the man is 125 N.