Answer:
177.65
Explanation:
Work done by the force field,F along path C is given by:
Given that:
![F(r(t))=(t-sin \ t)i+(3-cos \ t)j\\\\\\W=\int\limits_C F.dr\\=\int\limits^{6\pi}_0(t-sin \ t)i+(3-cos \ t)j).((1-cos \ t)i+sin \ t \ j)dt\\\\=\int\limits^{6\pi}_0(t-sin \ t)(1-cos \ t)+(3-cos \ t)sin \ t \ dt\\\\=\int\limits^{6\pi}_0t-tcos \ t+2sin\ t\ dt\\\\=\int\limits^{6\pi}_0-tcos \ t\ dt+[\frac{t^2}{2}-2cos \ t]\limits^{6\pi}_0\\\\=-I+177.65](https://tex.z-dn.net/?f=F%28r%28t%29%29%3D%28t-sin%20%5C%20t%29i%2B%283-cos%20%5C%20t%29j%5C%5C%5C%5C%5C%5CW%3D%5Cint%5Climits_C%20F.dr%5C%5C%3D%5Cint%5Climits%5E%7B6%5Cpi%7D_0%28t-sin%20%5C%20t%29i%2B%283-cos%20%5C%20t%29j%29.%28%281-cos%20%5C%20t%29i%2Bsin%20%5C%20t%20%5C%20j%29dt%5C%5C%5C%5C%3D%5Cint%5Climits%5E%7B6%5Cpi%7D_0%28t-sin%20%5C%20t%29%281-cos%20%5C%20t%29%2B%283-cos%20%5C%20t%29sin%20%5C%20t%20%5C%20dt%5C%5C%5C%5C%3D%5Cint%5Climits%5E%7B6%5Cpi%7D_0t-tcos%20%5C%20t%2B2sin%5C%20t%5C%20dt%5C%5C%5C%5C%3D%5Cint%5Climits%5E%7B6%5Cpi%7D_0-tcos%20%5C%20t%5C%20dt%2B%5B%5Cfrac%7Bt%5E2%7D%7B2%7D-2cos%20%5C%20t%5D%5Climits%5E%7B6%5Cpi%7D_0%5C%5C%5C%5C%3D-I%2B177.65)
#Integrating I by parts:
![I=\int\limits^{6\pi}_0 tcos \ t \ dt\\\\=[\int \ tcos \ t \ dt]\limits^{6\pi}_0\\\\=[t\int cos \ t \ dt-\int (\frac{dt}{dt}\intcos \ t \ dt)dt]\limits^{6\pi}_0\\\\=[tsin\ t -\int sin\ t \ dt]\limits^{6\pi}_0\\\\=0](https://tex.z-dn.net/?f=I%3D%5Cint%5Climits%5E%7B6%5Cpi%7D_0%20tcos%20%5C%20t%20%5C%20dt%5C%5C%5C%5C%3D%5B%5Cint%20%5C%20tcos%20%5C%20t%20%5C%20dt%5D%5Climits%5E%7B6%5Cpi%7D_0%5C%5C%5C%5C%3D%5Bt%5Cint%20cos%20%5C%20t%20%5C%20dt-%5Cint%20%28%5Cfrac%7Bdt%7D%7Bdt%7D%5Cintcos%20%5C%20t%20%5C%20dt%29dt%5D%5Climits%5E%7B6%5Cpi%7D_0%5C%5C%5C%5C%3D%5Btsin%5C%20t%20-%5Cint%20sin%5C%20t%20%5C%20dt%5D%5Climits%5E%7B6%5Cpi%7D_0%5C%5C%5C%5C%3D0)
Hence, work done is 177.65
Please help me with the unit assessment i have no idea any of the answers
A dishwasher and a dryer im not sure if that is right but that’s what I would put
Planck's constant. A physical constant adopted in 2011 by the CGPM.
Hello. You did not enter the data to which this question refers, which makes it impossible for it to have an exact answer. However, I will try to help you in the best possible way.
The forces that hold the elements together are called intermolecular forces. They are formed by covalent bonds between the molecules and can be called: dipole-induced (occurs between nonpolar molecules that have a negative pole and a positive pole) and dipole-dipole (occurs between polar moileculas, except when hydrogen is present).
