<span>In this problem, we need to solve for Bubba’s mass. To do this, we let A be the area of the raft and set the weight of the displaced fluid with the raft alone as ρwAd1g and ρwAd2g with the person on the raft, </span>where ρw is the density of water, d1 = 7cm, and d2= 8.4 cm. Set the weight of displaced fluid equal to the weight of the floating objects to eliminate A and ρw then solve for m.
<span>ρwAd1g = Mg</span>
ρw<span>Ad2g = (M + m) g</span>
<span>d2∕d1 = (M + m)/g</span>
m = [(d2<span>∕d1)-1] M = [(8.4 cm/7.0 cm) - 1] (600 kg) =120 kg</span>
This means that Bubba’s mass is 120 kg.
Answer:
the final angular speed of the wheel at the bottom is 25.5 rad/s
Explanation:
The computation of the final angular speed of the wheel at the bottom is as follows:
As we know that
Hence, the final angular speed of the wheel at the bottom is 25.5 rad/s
We simply applied the above formula so that the final angular speed could come
As we know that here gun + bullet system is isolated from all other external force system
so here the momentum of system is always conserved
so we will say
here we know that
now we will have
by solving above equation we will have
1st find the slope of the line:
(11-5)/(8.2-2.3) = 6/5.9 = 1.01
Find the equation of the line:
y - 5 = 1.01(x - 2.3)
y - 5 = 1.01x - 2.323
y = 1.01x + 2.667
Now set x to 20
y = 1.01(20) + 2.667
y = 20.2 + 2.667
y = 22.867 floors ~ 23 floors
