Answer:
1)Na2O
let the valency of Na is x
2(x)+(2)=0
2x+2=0
2x=-2
x=-1
2)ZnO
let the valency of Zn is x
x+2=0
x=-2
3)Al2O3
let the valency of Al is x
2(x)+3(2)=0
2x+6=0
2x=-6
x=-3
4)MgO
let the valency of Mg is x
x+2=0
x=-2
1) Balance of mass
CxHyOz + O2 ---> CO2 + H20
0.880 g + X = 1.760g + 0.720 g
=> X = 1.760g + 0.720g - 0.880g = 1.6 g of O2
2) C in CO2:
molar mass of CO2 = 44 g/mol
=> 12 g C / 44 g CO2 * 1.760 g CO2 = 0.480 g C
3) H in H2O
molar mass of H2O = 18.0 g/mol
2 g H / 18.0 g H2O * 0.720 g H2O = 0.080 g H
4) O
4a) O in CO2: 32gO / 44 g CO2 * 1.760 g CO2 = 1.280 g O
4b) O in H2O: 16gO / 18 gH2O * 0.720 g H2O = 0.640 g O
4c) O in CxHyOz = 1.280 g + 0.64 g - 1.6 g = 0.320 g O
5) Convert grams into moles
C: 0.480 g / 12 g/mol = 0.04 mol
H: 0.08 g / 1 g/mol = 0.08 mol
O: 0.32 g / 16 g/mol = 0.02 mol
6) Divide by the smallest number
C: 0.04 / 0.02 = 2
H: 0.08 / 0.02 = 4
O: 0.02 / 0.02 = 1
7) Use those numbers as subscripts for the empirical formula:
C2 H4 O
Answer: C2H4O
The lysis reaction with the formation of two different gases, and the synthesis reaction with the reaction of hydrogen and oxygen support that water is a compound and not an element.
<h3>What is electrolysis?</h3>
The electrolysis is the analytical process for the separation or the deposition of the element in the presence of the electric field.
The passing of electric current through water results in the release of two types of gases. Thus, it can be said that water lysis or breakdown forms the release of two elements hydrogen and oxygen supporting the fact that water is a compound and not an element.
The production of water is found to be formed with the reaction of hydrogen with oxygen. Thus it supports that water is a compound and, not an element.
Learn more about electrolysis, here:
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Answer:
Mass = 206.38 g
Explanation:
Given data:
Mass of calcium chloride = 80.0 g
Mass of silver chloride formed = ?
Solution:
Chemical equation:
CaCl₂ + 2AgNO₃ → Ca(NO₃)₂ + 2AgCl
Number of moles of CaCl₂:
Number of moles = mass/molar mass
Number of moles = 80.0 g/ 110.98 g/mol
Number of moles = 0.72 mol
Now we will compare the moles of CaCl₂ and AgCl
CaCl₂ : AgCl
1 : 2
0.72 : 2/1×0.72 = 1.44 mol
Mass of silver chloride:
Mass = number of moles × molar mass
Mass = 1.44 mol × 143.32 g/mol
Mass = 206.38 g