Answer:
B
Explanation:
machanical waves like sea waves need a medium.
but electromagnetic waves never need a medium
but can also travel through medium
Method 1:
First find out the formula of the sample.
no. of moles of O = 25.6/16 = 1.6
no. of moles of C = 9.6/12 = 0.8
ratio of C:O = 1:2
formula is CO2
In the second sample,
no. of moles of O = 21.6/16 = 1.35
no. of moles of C = 1.35/2 = 0.675
mass of C = 0.675 x12 = 8.1g
method 2:
Actually it’s quite simple. The two samples are the same compound so the elements produced should be in the same ratio.
C/9.6 = 21.6/25.6
C = 8.1g
Aside from the high-energy molecules like ATP and NaDH . The net reaction for the complete oxidation of acetyl-COA in the TCA cycle is given as ,
Pyruvate → 3
The reaction of the cycle are carried out by eight enzymes that completely oxidize acetate ( a two carbon molecule ) , in the form of acetyl-COA , into two molecules each of carbon dioxide and water . The net yield of one turn of the TCA cycle in terms of energy - containing compounds is one GTP , one FADH2 , and three NADH molecules . The NADH molecules are used in oxidative
To learn more about acetyl-COA
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Answer:
0.0428 M
Explanation:
Because we're asked to calculate the molarity of nickel(II) cation, we need to <u>determine all sources for that species</u>, in this case, all Ni⁺² comes from the nickel(II) bromide solid (NiBr₂).
We use the molecular weight of NiBr₂ to calculate the moles of Ni:
1.87 g NiBr₂ ÷ 218.49g/mol * (1molNi⁺²/1molNiBr₂) = 8.55x10⁻³ mol Ni⁺²
Then we <u>divide the moles by the volume in order to calculate the concentration</u>:
8.55x10⁻³ mol Ni⁺² / 0.200 L = 0.0428 M