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wolverine [178]
3 years ago
8

Where are reactive metals found?

Chemistry
1 answer:
Charra [1.4K]3 years ago
4 0
On the left of the periodic table
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What do scientists use to deterimine the temperature of a star
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Measure the brightness of a star through two filters and compare the ratio of red to blue light.
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An atom's nucleus has 92 protons and its mass number is 235. how many neutrons are in the nucleus? what is the name of the atom
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The mass number is the sum of the protons and neutrons in an atom. 235-92 = 143 neutrons.
Element 92 is Uranium.

Uranium is also the highest atomic number element which exists in nature. All of the rest above element 92 only exist nuclear high-energy reactions (the transuranium elements), and most experience nuclear decay very quickly and form other elements with fewer protons. 
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The Lewis diagram for BH2 is:
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Answer:

Electron pair geometry- trigonal planar

There is one lone pair around the boron atom

The geometry of BH2 is bent

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The valence shell electron pair repulsion theory offers a frame work for determining the shape of molecules based on the number of electron pairs of the valence shell of the central atom in the molecule.

In BH2-, the central atom is boron. There is a lone pair on boron. Owing to the lone pair on boron, the molecular geometry of BH2 is bent.

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What is the land like where mesosaurus fossils are found?
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Answer:

They are found in South America and African Plates. Earths outer layer is made out of solid rock. These fossils are sometimes discovered closer to the mantle; the mantle is between the crust and the earths super-heated core!

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3 0
2 years ago
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Write a balanced half-reaction describing the reduction of aqueous vanadium(V) cations to aqueous vanadium(I) cations.
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Explanation:

Reduction is a chemical reaction in which electrons are gained by one of the atoms taking part in the reaction and lowering of an oxidation state of that atom.

Reduction takes place at the cathode.

In aqueous, vanadium(V) is present in +5 oxidation state which on reduction changes to vanadium(I) with +1 oxidation state.

The half reaction is :

V^{5+}(aq)+4e^- \rightarrow V^{1+}(aq)


5 0
3 years ago
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