An ideal Diesel cycle has a compression ratio of 17 and a cutoff ratio of 1.3. Determine the maximum temperature of the air and
the rate of heat addition to this cycle when it produces 140 kW of power and the state of the air at the beginning of the compression is 90 kPa and 578C. Use constant specific heats at room temperature.
1 answer:
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Answer:
<em>Heat rejected to cold body = 3.81 kJ</em>
Explanation:
Temperature of hot thermal reservoir Th = 1600 K
Temperature of cold thermal reservoir Tc = 400 K
<em>efficiency of the Carnot's engine = 1 - </em><em> </em>
eff. of the Carnot's engine = 1 -
eff = 1 - 0.25 = 0.75
<em>efficiency of the heat engine = 70% of 0.75 = 0.525</em>
work done by heat engine = 2 kJ
<em>eff. of heat engine is gotten as = W/Q</em>
where W = work done by heat engine
Q = heat rejected by heat engine to lower temperature reservoir
from the equation, we can derive that
heat rejected Q = W/eff = 2/0.525 = <em>3.81 kJ</em>
Answer: Volume= 1.16 yd³
Explanation:
We are given the in-situ moisture content= 18% and moist unit weight= 105 pcf
First we find out the dry unit weight
Dry unit weight= Moist unit weight / (1+ moisture content)
Dry unit weight=
Dry unit weight= 88.983 pcf
Now, to find the volume ( in terms of each cubic yard i.e 1 yd³ we have
Volume = Dry unit weight compacted / Dry unit weight (in-situ) * 1 yd³
Volume=
Volume= 1.16 yd³