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S_A_V [24]
3 years ago
5

A First Stage in a turbine receives steam at 10 MPa, 800 C with an exit pressure of 800 KPa. Assume the stage is adiabatic and r

eversible. Find the exit temperature and the specific work.
Engineering
1 answer:
9966 [12]3 years ago
7 0

Answer

given,

P₁  = 10 MPa                 T₁ = 800

P₂ = 800 KPa               T₂ = ?

Using formula

\dfrac{T_2}{T_1} = (\dfrac{P_2}{P_1})^{\dfrac{n-1}{n}}

For steam   n = 1.33                    

\dfrac{T_2}{800+273} = (\dfrac{800\times 10^{3}}{10\times 10^{6}})^{\dfrac{1.33-1}{1.33}}

T₂ = 573.368 K                    

T₂ = 573.368 - 273 = 300.368 °C

W = \dfrac{P_1V_1-P_2V_2}{n-1}

          =\dfrac{mR(T_1-T_2)}{n-1}

          =\dfrac{1\times 0.287\times (800 - 300.368)}{1.33-1}

      W = 434.53 kJ/kg

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timama [110]

Answer: Weight on Mars = 0.02593N

Explanation:

Given; Circumference C of Sphere = 70cm = 0.7m,

Specific Gravity S. G. of material = 1.21,

acceleration due to gravity in the Mars gm = 3.7m/s^2

We know that Weight W = mass m × acceleration due to gravity.

Let the Weight in on the Mars be Wm.

Wm = m × gm

Since we are given gm, we need to calculate for m. (Note that mass m is the same everywhere)

But mass = specific gravity × volume

Since we know the specific gravity, let's go ahead to calculate for the volume of the ball.

We know that Volume of a Sphere V = (4/3)πr^3

To get r, we know that C = 2πr

Therefore, r = C/(2π) = 0.7/(2π) = (7/10)/2π = 7/20π (in meters)

V = (4/3)*π×(7/20π)^3 = 343/6000π^2 (in meter^3)

m = 343/6000π^2 × 1.21 = 7.01×10^(-3)kg

Wm = 7.01×10^(-3) × 3.7 = 0.02593N

8 0
3 years ago
Select the correct answer. which process involves creating a product by heating metals and changing their shape through the appl
Paraphin [41]

Answer:

I would say that it is forming.

Explanation:

Give brainliest if u can. :S

4 0
2 years ago
Microchips found inside most electronic devices today are examples of what material A. Polymers B. Alloys C. Composites D. None
dedylja [7]

Answer: A

Explanation:

Microchips are made out of silicone witch is a polymer.

6 0
3 years ago
Read 2 more answers
Implement this C program by defining a structure for each payment. The structure should have at least three members for the inte
Klio2033 [76]

Answer:

#include<stdio.h>

#include<math.h>

void output_amortized(float loan_amount,float intrest_rate,int term_years)

{

  int i,j;                       //Month

  int payments;                   //Number of payments  

  float loanAmount;               //Loan amount

  float anIntRate;               //Yealy interest Rate

  float monIntRate;               //Monthly interest rate

  float monthPayment;           //Monthly payment

  float balance;                   //Balance due

  float monthPrinciple;           //Monthly principle paid

  float monthPaidInt;           //Month interest paid

 

  balance=loan_amount;

  //Calculations

  //Monthly interest rate

  monIntRate = ((intrest_rate/(100*12)));

  //Monthly payment

  payments=term_years;  

  monthPayment = (loan_amount * monIntRate * (pow(1+monIntRate, payments)/(pow (1+monIntRate, payments)-1)));

  monthPaidInt = balance * monIntRate;

  //Amount paid to principle

  monthPrinciple = monthPayment-monthPaidInt;

  //New balance due

  balance = balance - monthPrinciple;

 

  printf("\n\nMonthly payment should be :%.2f\n\n",monthPayment);

  printf("============================AMORTIZATION SCHEDUAL==========================\n");

  printf("#\tPayment\t\tIntrest\t\tPrinciple\t\tBalance\n");

 

  for(i=0;i<payments;i++)

  {

      printf("%d%9c%.2f%9c%.2f%16c%.2f%14c%.2f\n",(i+1),'$',monthPayment,'$',monthPaidInt,'$',monthPrinciple,'$',balance);

      monthPaidInt = balance * monIntRate;

      //Amount paid to principle

      monthPrinciple = monthPayment-monthPaidInt;

      //New balance due

      balance = balance - monthPrinciple;

  }

}

int main()

{

  float principle,rate;

  int termYear;

  printf("Enter the loan amount: $");

  scanf("%f",&principle);

  printf("Enter the intrest rate :%");

  scanf("%f",&rate);

  printf("Enter the loan duration in years: ");

  scanf("%d",&termYear);

  output_amortized(principle,rate,termYear);

}

Explanation:

see output

6 0
3 years ago
Train levels a station and travels north at 60km/hr. Two hours later, a second train leaves on a parallel track and travels nort
Amanda [17]

Answer: they would be 300 miles from the station.

Explanation:

At the point where both trains meet, they would have covered the same distance.

Let t represent the time spent by the first train in covering this distance.

Distance = speed × time

The first train leaves the station and travels north at 60km/hr.

Distance covered by the first train is

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Two hours later, a second train leaves on a parallel track and travels north at 100km/hr. Time spent by the second train in covering this distance is (t - 2) hours

Distance covered by the second train is

100(t - 2) = 100t - 200

Since both trains covered the same distance, then

100t - 200 = 60t

100t - 60t = 200

40t = 200

t = 200/40

t = 5 hours

The distance that they would be from the station is

60 × 5 = 300 miles

6 0
3 years ago
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