Answer:
v = 54m/s
Explanation:
a = 7m/s²
u = 12m/s
t = 6s
7 = (v-12)/6
v - 12 = 42
v = 54m/s
(Correct me if i am wrong)
Think and discuss: Think about the process of finding the ideal conditions.A.Why would it be hard to find the ideal light intens
1 answer:
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Answer:
108 extended days
Explanation:
Regular school hours a day = 6 hr
No. of school days to make up by extending the regular hours = 3 days
Amount of time added to the regular hours of school = 10 min
No. of extended school days to make up the 3 school days by following the above mentioned criteria be x.
Time of school hours in 3 days =
are required to make up 3 days of school having 6 hours of regular timing with 10 minutes of add-on time each day.
Answer:
48.16 %
Explanation:
coefficient of restitution = 0.72
let the incoming speed be = u
let the outgoing speed be = v
kinetic energy = 0.5 x mass x
- incoming kinetic energy = 0.5 x m x
- coefficient of restitution =
0.72 =
v = 0.72u
therefore the outgoing kinetic energy = 0.5 x m x
outgoing kinetic energy = 0.5 x m x
outgoing kinetic energy = 0.5184 (0.5 x m x )
recall that 0.5 x m x is our incoming kinetic energy, therefore
outgoing kinetic energy = 0.5184 x (incoming kinetic energy)
from the above we can see that the outgoing kinetic energy is 51.84 % of the incoming kinetic energy.
The energy lost would be 100 - 51.84 = 48.16 %