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TiliK225 [7]
2 years ago
13

A bicyclist was moving at a rate of 3 m/s, and then sped up to 4 m/s. If the cyclist has a mass of 100 kg, how much work was nee

ded to increase his velocity? (Hint: Use the work-kinetic energy theorem.) O A. 1250 J B. 450 J O c. 350 j D. 800 J​
Physics
1 answer:
kotegsom [21]2 years ago
7 0

Answer:

i got b but urs is a little different tell me if right

Explanation:

i go 100 on my test

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Help please <br><br><br> What is elastic potential energy
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Elastic Potential Energy. Elastic potential energy is Potential energy stored as a result of deformation of an elastic object,

Explanation:

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3 years ago
La capital de Puerto Rico es _____.
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La capital de Puerto Rico es la ciudad "San Juan".

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Because it may erode his skin?

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A Ping-Pong ball is given an upward initial velocity. The force of air resistance causes the times of ascent and descent to be u
bazaltina [42]

Answer:

Time of ascent is greater than time of descent.

Explanation:

The gravitational force always acts in the downward direction. The air drag always opposes the motion.

During ascent, the gravitational force and air drag act in opposite direction to the motion where as during descent, only air drag acts in opposite direction to the motion of the ball while gravitational force acts in the same direction. Thus, the time of ascent and descent become unequal with time of ascent being greater than time of descent.

5 0
3 years ago
Water drips from the nozzle of a shower onto the floor 193 cm below. The drops fall at regular (equal) intervals of time, the fi
Law Incorporation [45]

Answer: 108.81 cm and 48.66 cm

Explanation:

In this, we have to make sure to keep in mind the Gravity effects on the drops. The drops will accelerate when they fall making them travel faster. This means, the velocity is not constant.

What is know:

Height (h) = 193 cm

Gravity (g) =  981 cm/s^{2}

Initial Velocity = 0

First, we can know how long it take to the drop to travel to the floor. It can be done with the following equation:

x = V_{0} t + \frac{1}{2} at^{2}    (1)

Where:

x is the distance which is 193cm

Vo is the Initial Velocity  which is zero

t is the time the time it takes the drop to travel from the shower to the floor

a is the aceleration, which in this case is the gravity.

With the Initial Velocity equals zero the equations simply:

193 cm = \frac{1}{2}gt^{2}

To search for the time:

t =\sqrt{\frac{2*193cm}{981cm/s^{2} } }

t = 0.627 s

This is the time it takes a drop to fall to the floor, with this time and knowing other 3 drops have driped from the shower by this time. We can calculate how much time it takes the shower to drip each drop.

Time for Drip = t/4

Time for Drip = 0.156

This time is the difference between each drop, using the same equation we can calculate where was each drop, because now it is know how much time had each drop after being drip from the shower.

Our first is already on the floor (193 cm) with 0.627 s, The second drops have been falling for (0.627s - 0.156) 0.471 s and our third drop for (0.627s - 0.156 - 0.156) 0.315 s

We can use (1) to know how far have each drop traveled on these times. We know the Initials Velocity are 0, know we need ot know the distances.

For the second drop:

x = \frac{1}{2} (981cm/s^{2})(0.471s)^{2}

x =108.81 cm

For the third drop:

x = \frac{1}{2} (981cm/s^{2})(0.315s)^{2}

x = 48.66 cm

8 0
3 years ago
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