Answer:
The diameter of the oil molecule is
.
Explanation:
Mass of the oil drop = ![m=9.00\times 10^{-7} kg](https://tex.z-dn.net/?f=m%3D9.00%5Ctimes%2010%5E%7B-7%7D%20kg)
Density of the oil drop = ![d=918 kg/m^3](https://tex.z-dn.net/?f=d%3D918%20kg%2Fm%5E3)
Volume of the oil drop: v
![d=\frac{m}{v}](https://tex.z-dn.net/?f=d%3D%5Cfrac%7Bm%7D%7Bv%7D)
![v=\frac{m}{d}=\frac{9.00\times 10^{-7} kg}{918 kg/m^3}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bm%7D%7Bd%7D%3D%5Cfrac%7B9.00%5Ctimes%2010%5E%7B-7%7D%20kg%7D%7B918%20kg%2Fm%5E3%7D)
Thickness of the oil drop is 1 molecule thick.So, let the thickness of the drop or diameter of the molecule be x.
Radius of the oil drop on the water surface,r = 41.8 cm = 0.418 m
1 cm = 0.01 m
Surface of the sphere is given as: a = ![4\pi r^2](https://tex.z-dn.net/?f=4%5Cpi%20r%5E2)
![a=4\times 3.14\times (0.418 m)^2=2.1945 m^2](https://tex.z-dn.net/?f=a%3D4%5Ctimes%203.14%5Ctimes%20%280.418%20m%29%5E2%3D2.1945%20m%5E2)
Volume of the oil drop = v = Area × thickness
![\frac{9.00\times 10^{-7} kg}{918 kg/m^3}=2.1945 m^2\times x](https://tex.z-dn.net/?f=%5Cfrac%7B9.00%5Ctimes%2010%5E%7B-7%7D%20kg%7D%7B918%20kg%2Fm%5E3%7D%3D2.1945%20m%5E2%5Ctimes%20x)
![x= 4.4674\times 10^{-10} m= 4.4674\times 10^{-8} cm](https://tex.z-dn.net/?f=x%3D%204.4674%5Ctimes%2010%5E%7B-10%7D%20m%3D%204.4674%5Ctimes%2010%5E%7B-8%7D%20cm)
The thickness of the oil drop is
and so is the diameter of the molecule.
Answer:
5.6 L
Explanation:
We can apply Charles' Law here since our pressure is constant (will not change inside the refrigerator) and we are relating change in volume with change in temperature:
V₁ / T₁ = V₂ / T₂ where V₁ and T₁ are initial volume and temperature, and V₂ and T₂ are final volume and temperature. Let's plug in what we know and solve for the unknown:
28.0 L / 25 °C = V₂ / 5 °C => V₂ = 5.6 L
5.6 L is our new volume (at 5 °C).
To be honest I don’t even know
Density is an intrinsic property, so it is independent of the amount of substance present: one gold coin would have the same density as a solid gold boulder.
So if the density of gold is 19.3 g/cm³, the density of a bar of gold and the pieces into which the bar is cut would all be 19.3 g/cm³.
There is acetone, xylene, and toluene in spray paint