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3 years ago

A sample of hydrogen gas occupies a volume of 4.1 Liters

Chemistry

1 answer:

BigorU [14]3 years ago

8 0

Answer:

p2=172.2KPA

Explanation:

use Boyle's law

p1 x v1 = p2 x v2

p1= 105 kpa

v1=4.1L

p2= ?

v2= 2.5L

substitute;

105 x 4.1 = p2 x 2.5

p2= ( 105 x 4.1)\2.5

p2=172.2KPA

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The molecular formula of this compound is C3H603 XD

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3 years ago

Sample of 200mls of 0.5 sulphuric acid,was asked to produce 1.2M of the new solution.Calculate the volume of the new solution

AlladinOne [14]

Answer:

$V_2=83.3mL$

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the volume of the new solution by using the general formula of dilution:

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3 years ago

What did Dalton’s atomic theory teach

sweet-ann [11.9K]

Answer:

All matter is composed of atoms.

Atoms are not destructible.

Compounds formation occur by the combination of one or different types of atoms

In the chemical reactions, atoms are rearranged.

The atom of the same elements are similar in size and properties and the Atoms of the different elements are different in size and properties.

Explanation:

<u>John Dalton has developed the Dalton atomic theory.</u>

Dalton atomic theory was the first to explain that all matters composed of atoms and its properties, the atom as the smallest particle which cannot be destroyed and damaged.

This theory was based on the <u>law of conservation of mass and law of constant composition.</u>

His theory was accepted by many scientists.

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3 years ago

Read 2 more answers

Now let us refine our model by noting that there is a second source of Na+ ions in the cell: NaI. Suppose the outside of the cel

MArishka [77]

Answer:

$E=55mV$

Explanation:

Hello,

Considering the given information, the new concentration of Na+inside will be (13.6 + 4) mM = 17.6 mM, and outside will be (150 + 0.04) mM = 150.04 mM due to the previous specified conditions.

Now, the recalculation of the Nerst potential at the supposed temperature of 25 °C (which is modifiable) is done via:

$E=\frac{RT}{zF} ln(\frac{C_{Na^+,outside}}{C_{Na^+,outside}} )\\\\E=\frac{8.314\frac{J}{mol*K}*298K}{1*9.65x10^4\frac{C}{mol} } *ln(\frac{150.04}{17.6} )=0.055V*\frac{1x10^3mV}{1V} \\E=55mV$

Best regards.

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3 years ago

The theoretical yield of ammonia in an industrial synthesis was 550 kg, but only 480 kg was obtained. What was the percentage yi

bezimeni [28]

Theoretical yield 550 kg - 100%

Actual yield 480 kg - x%

x= 480*100/550 ≈ 87.3 %

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3 years ago