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Marysya12 [62]
3 years ago
13

True or false Plow is a back stretch

Physics
2 answers:
VashaNatasha [74]3 years ago
5 0

Answer:

T

Explanation:

Keith_Richards [23]3 years ago
3 0
True. Also stretches shoulders and other things
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3. Waxing means "growing." Waning means
Sonja [21]

Answer:

I think it is the last one.

Explanation:

I am not sure because i am stuck on this one, too.

4 0
3 years ago
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For Valentine’s Day, Sally received a helium-filled balloon at a party. On returning home she accidentally left the balloon in t
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Answer:

If the temperature of the air in the balloon is less than the temperature of the air surrounding the balloon then the balloon will appear slightly deflated because of the difference in temperature.

As the temperature of the air in the balloon reaches the surrounding air temperature, then the balloon will appear to be fully inflated because the temperature of the air in the balloon is the same as the surrounding air temperature.

8 0
3 years ago
A neutral boron atom has 6 neutrons and 5 electrons. How many protons does it have? Select one: a. 7 b. 6 c. 5 d. 4
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If the atom is neutral, it has the same number of protons as electrons. If there are 5 electrons, there are also 5 protons.
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3 years ago
Calculating the Mass of a Granite Monument
Volgvan

Answer:

m = 684,865,8 g

Step-by-step explanation

V = 25,365.4 cm^3            Is volume

r = 27g/cm^3                     Is density

To calculate mass you use formula:

m= V*r

m = 25,365.4 x 27

m = 684,865,8 g

8 0
2 years ago
A student, who weighs 720N, is standing on a bathroom scale and riding an elevator that is moving downwards with a speed that is
jasenka [17]

Answer:

1) The mass of the student is approximately 73.39 kg

2) The net force on the student is approximately 947.523 N

3) The value the scale will read is approximately 96.59 kg

Explanation:

The given parameters are;

The weight of the student = 720 N

The speed at which the elevator is decreasing = 3.1 m/s²

1) The weight of the student = The mass of the student × The acceleration due to gravity

The acceleration due to gravity is a constant = 9.81 m/s²

Substituting the known values gives;

720 N = The mass of the student × 9.81 m/s²

∴ The mass of the student = 720 N/(9.81 m/s²) ≈ 73.39 kg

2) The forces acting on the student are;

i) The force of gravity which is the weight of the student acting downwards

ii) The inertia force of the slowing elevator acting downwards in the same direction as the weight of the student

The net force, F_{net} = The weight of the student + The inertia force of the slowing elevator

∴ The net force, F_{net} = 720 N + 73.39 kg × 3.1 m/s² ≈ 947.523 N

3) The scale will read the mass of the student as follows;

Mass reading of student on the scale = Force on scale/9.81

∴ Mass reading of student on the scale = 947.523/9.81 ≈ 96.59 kg

The value the scale will read = 96.59 kg.

3 0
3 years ago
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