Answer:
The option C is the false statement
Explanation:
Ionization energy is the energy needed to completely pull out an electron from the valence electron of a gaseous atom.
The given values of ionization energy (kJmol⁻) for a main group element is: IE₁ = 100; IE₂ = 2200; IE₃ = 3300; IE₄ = 4100; IE₅ = 5200
Since<u> first ionization energy is very low</u> and the <u>difference between the first and the second ionization energy</u> for the given element is <u>very high</u>.
Therefore, <u>the given chemical element is most likely an alkali metal</u> belonging to the<u> group IA of the periodic table.</u>
As the alkali metals react with oxygen to form oxides. So, the given <u>element (J</u>) can react with oxygen to form <u>oxide of the formula J₂O</u>.
Since the given element has <u>low first ionization energy, thus it is reactive</u>. Therefore, the given element <u>can not exist as a free element.</u>
If the given chemical element belongs to <u>the period 3</u> of the periodic table, then it is should be the group IA alkali metal,<u> sodium</u>.
<u>Therefore, option C is the false statement.</u>
Answer: did she conect the wire to de batery?
Answer:
This was important because it supported the concept of discovery of new elements
Explanation:
Mendleev left gaps in his table not discovered at that time, but he predicted the properties (chemical and physical) of undiscovered elements. Mendeleev left the gap next to silicon and named the undiscovered element as 'eka-silicon', the element germanium was discovered later.
Https://www.khanacademy.org/science/chemistry/chemical-reactions-stoichiome/stoichiometry-ideal/v/stoichiometry-example-problem-2 this should explain
Answer:
understanding people, organize notes correctly, learn how to organize your time wisely.
Explanation: