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Nady [450]
3 years ago
15

When the electron cloud of a molecule is easily distorted, the molecule has a high _____________.a. polarity b. polarizability c

. dipole moment d. van der Waals radius
Chemistry
1 answer:
katovenus [111]3 years ago
6 0

Answer: Option (b) is the correct answer.

Explanation:

Polarity is defined as the development of partial charges on the atoms of a molecule.

Whereas polarizability is defined as the ability or measure of how readily an electron cloud is able to get distorted. More is the polarizability more will be the electron is distorted in nature.

A dipole moment is defined as the measurement of the separation of two opposite electrical charges.

Thus, we can conclude that when the electron cloud of a molecule is easily distorted, the molecule has a high polarizability.

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Colligative properties depend on the amount of solute dissolved in a solvent. These set of properties do not depend on the type of species present. These properties include freezing point depression, boiling point elevation, osmotic pressure and vapor pressure lowering.
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3 years ago
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Acids & bases/concentration A mixture is made by mixing 425 mL of 0.94 M H2SO4 with 750. mL of 0.83 M NaOH. (a) What is the
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Answer:

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3 years ago
What is the balenced equation of Cu+H2SO4---> CuSO4+H2O+SO2
algol [13]
Balanced chemical equation :

1 Cu + 2 H2SO4 = 1 CuSO4 + 2 H2O + 1 SO<span>2</span>

hope this helps!.

8 0
3 years ago
Consider the chemical equations shown here.
vichka [17]

P₄0₆_{s} + 20₂_{g}   ⇒    P₄0₁₀_{s}

Explanation:

The overall equation for the reaction that produces  P₄0₁₀ is :

P₄0₆_{s} + 20₂_{g}   ⇒    P₄0₁₀_{s}

Now let us derive this equation:

Given equations:

   P₄_{s} + 30₂_{g}  ⇒ P₄0₆_{s}  equation 1;

   P₄_{s} + 50₂_{g} ⇒  P₄0₁₀_{s}  equation 2;

To get the overall combined equation, the equation 1 must be reversed and added to equation 2:

            P₄0₆_{s} ⇒ P₄_{s} + 30₂_{g}   equation 3

                      +

            equation 2:

 P₄_{s} + 50₂_{g}  +    P₄0₆_{s}  ⇒  P₄0₁₀_{s}  +  P₄_{s} + 30₂_{g}  

cancelling specie that appears on both sides and removing excess oxygen gas on the reactant side gives;

   

                  P₄0₆_{s} + 20₂_{g}   ⇒    P₄0₁₀_{s}

learn more:

Net equation brainly.com/question/2947744

#learnwithBrainly

5 0
3 years ago
What is the molarity of a solution containing 12.0 g of NaOH in 250.0 mL of solution?
riadik2000 [5.3K]

Answer:

1.196 M NaOH

Explanation:

Molarity = moles/Volume (L)

moles NaOH = mass NaOH/MM NaOH = 12/40.01 = 0.299 moles NaOH

Volume solution = 250 mL = 0.250L

M = 0.299/0.250=1.196 M NaOH

3 0
3 years ago
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