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lbvjy [14]
3 years ago
11

If the cat travels a total distance of 27.9 m in 3.2 seconds what will the cats speed be

Physics
2 answers:
mr_godi [17]3 years ago
4 0

Answer:8.71875m/s

Explanation:

Distance(d)=27.9m time(t)=3.2seconds

Speed=distance/time

Speed=27.9/3.2

Speed=8.71875m/s

Arada [10]3 years ago
4 0

Answer:

8.71875

Explanation:

speed = distance÷time

distance= 27.9

time= 3.2

27.9 ÷ 3.2 = 8.71875

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Brain-powered cars?
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3 years ago
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A sphere of mass of 1.55 kg is accelerated upwards by a string to which the sphere is attached. Its speed increases from 2.81 m/
Mama L [17]

Answer:

The tension in the string is 16.24 N

Explanation:

Given;

mass of the sphere, m = 1.55 kg

initial velocity of the sphere, u = 2.81 m/s

final velocity of the sphere, v = 4.60 m/s

duration of change in the velocity, Δt = 2.64 s

The tension of the string is calculated as follows;

T =  ma  + mg\\\\T = m(a + g)\\\\where;\\\\a \ is \ upward \ acceleration \ of \ the \ sphere\\\\g \ is \ acceleration \ due \ to \ gravity =9.8 \ m/s^2\\\\a = \frac{\Delta V}{\Delta t} = \frac{v- u}{ t} = \frac{4.6 - 2.81 }{2.64} = 0.678 \ m/s^2

T = 1.55(0.678 + 9.8)

T = 1.55(10.478)

T = 16.24 N

Therefore, the tension in the string is 16.24 N

5 0
3 years ago
According to Ohm’s law, the ratio of voltage to current in a conductor is
valina [46]

According to Ohm’s law, the ratio of voltage to current in a conductor is  constant.

Answer: Option A

<u>Explanation:</u>

Ohm's law defines that an electric current flowing through the conductor between two ends is directly proportionate to the voltage at these two points. The introduction of a constant proportionality, resistance, gives a simple mathematical equation describing this relationship. Particularly, Ohm's law also mentions that R is constant in this respect, i.e. not dependent on the current.

                                            I=\frac{V}{R}

Where,  

I is the current conduction in amperes

V is the voltage calculated by the conductor in volts

R is the conductor’s resistance in ohms.

3 0
3 years ago
A circuit containing an inductor and a capacitor in series is designed to have a resonant frequency of 4511 Hz. If the inductor
OLEGan [10]

Answer:

(e)6.835\times 10^{-7}F

Explanation:

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That is \omega L=\frac{1}{\omega C}

\omega ^2=\frac{1}{LC}

\omega =\frac{1}{\sqrt{LC}}

f=\frac{1}{2\pi \sqrt{LC}}

We have given resonance frequency f =4511 Hz and inductance L=1.82 mH

So 4511=\frac{1}{2\pi \sqrt{LC}}

LC=\frac{1}{4\pi ^2\times 4511^2}

LC=1.244\times 10^{-9}

C=\frac{1.244\times 10^{-9}}{1.82\times 10^{-3}}=0.6835\times 10^{-6}=6.835\times 10^{-7}F

So option e is the correct answer

3 0
3 years ago
Good afternoon.....from bangladesh....
Step2247 [10]

Answer:

good afternoon

Explanation:

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