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lbvjy [14]
3 years ago
11

If the cat travels a total distance of 27.9 m in 3.2 seconds what will the cats speed be

Physics
2 answers:
mr_godi [17]3 years ago
4 0

Answer:8.71875m/s

Explanation:

Distance(d)=27.9m time(t)=3.2seconds

Speed=distance/time

Speed=27.9/3.2

Speed=8.71875m/s

Arada [10]3 years ago
4 0

Answer:

8.71875

Explanation:

speed = distance÷time

distance= 27.9

time= 3.2

27.9 ÷ 3.2 = 8.71875

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A girl at an airport rolls a ball north on a moving walking that moves east. If the ball’s speed with respect to the walkway is
sweet-ann [11.9K]

We have to add two vectors.

Vector #1: 0.15 m/s north

Vector #2: 1.50 m/s east

Their sum:

Magnitude: √(0.15² + 1.50²)

Magnitude = √(0.0225+2.25)

Magnitude = √2.2725

Magnitude = <em>1.5075 m/s</em>

Direction = arctan(0.15/1.50) north of east

Direction = <em>5.71° north of east</em>

4 0
3 years ago
Consider a car travelling at 60 km/hr. If the radius of a tire is 25 cm, calculate the angular speed of a point on the outer edg
vlabodo [156]

To solve this problem it is necessary to apply the concepts given in the kinematic equations of movement description.

From the perspective of angular movement, we find the relationship with the tangential movement of velocity through

\omega = \frac{v}{R}

Where,

\omega =Angular velocity

v = Lineal Velocity

R = Radius

At the same time we know that the acceleration is given as the change of speed in a fraction of the time, that is

\alpha = \frac{\omega}{t}

Where

\alpha =Angular acceleration

\omega = Angular velocity

t = Time

Our values are

v = 60\frac{km}{h} (\frac{1h}{3600s})(\frac{1000m}{1km})

v = 16.67m/s

r = 0.25m

t=6s

Replacing at the previous equation we have that the angular velocity is

\omega = \frac{v}{R}

\omega = \frac{ 16.67}{0.25}

\omega = 66.67rad/s

Therefore the angular speed of a point on the outer edge of the tires is 66.67rad/s

At the same time the angular acceleration would be

\alpha = \frac{\omega}{t}

\alpha = \frac{66.67}{6}

\alpha = 11.11rad/s^2

Therefore the angular acceleration of a point on the outer edge of the tires is 11.11rad/s^2

5 0
3 years ago
A box having a mass of 0.2 kg is dragged across a horizontal floor by
Lyrx [107]

you can check attachment for answer.

kind regards

7 0
3 years ago
Some neodymium glass lasers can provide 100TW of power in 1.0 ns pulses at a wavelength of 0.26 micrometers. how much energy is
Aleksandr-060686 [28]

Answer:

 E = 10⁵ J

Explanation:

given,

Power, P = 100 TW

           = 100 x 10¹² W

time, t = 1 ns

           = 1 x 10⁻⁹ s

The energy of a single pulse is:-

Energy = Power x time

 E = P t

 E = 100 x 10¹² x 1 x 10⁻⁹

 E = 10⁵ J

The energy contained in a single pulse is equal to 10⁵ J

7 0
3 years ago
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