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lbvjy [14]
3 years ago
11

If the cat travels a total distance of 27.9 m in 3.2 seconds what will the cats speed be

Physics
2 answers:
mr_godi [17]3 years ago
4 0

Answer:8.71875m/s

Explanation:

Distance(d)=27.9m time(t)=3.2seconds

Speed=distance/time

Speed=27.9/3.2

Speed=8.71875m/s

Arada [10]3 years ago
4 0

Answer:

8.71875

Explanation:

speed = distance÷time

distance= 27.9

time= 3.2

27.9 ÷ 3.2 = 8.71875

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A ball is tossed straight up from the surface of a small, spherical asteroid with no atmosphere. The ball rises to a height equa
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Answer:

d. equal to one-fourth the acceleration at the surface of the asteroid.

Explanation:

The explanation is attached as a picture with this answer

Newton's law of universal gravitation is being used to compare the accelerations at the surface and at the top of the ball's path.

as it can be seen in the explanation that the proportional form of the equation is used because we do not need to necessarily use to final form with "G" for comparison calculations.

As per the given scenario only difference between the two points in the gravitational field is the distance from center of the spherical asteroid, i.e. r.

It is  taken 2r for the top is the path. hence we obtain (1/4)g as our answer.

4 0
3 years ago
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Bright and dark fringes are seen on a screen when light from a single source reaches two narrow slits a short distance apart. Th
Dima020 [189]

Answer:

Explanation:

Let the thickness of the film is t and the refractive index of the material of film is n.

When light travels through a sheet of thickness t, the optical path traveled is nt.

When the path of one of slit is covered by a sheet of thickness t, the optical path becomes

x = ( n - 1) t

As the one fringe is shift, so the optical path changed by one wavelength.

i.e., x = λ

So, λ = ( n - 1) t

t=\frac{\lambda }{n-1}

7 0
3 years ago
A toy cannon launches a 46-g golf ball straight up into the air with a kinetic energy of 6.8 J. What must the
Shkiper50 [21]

Answer : The correct option is, (C) 17 m/s

Explanation :

Formula used :

K.E=\frac{1}{2}mv^2

where,

K.E = kinetic energy = 6.8 J

m = mass of object = 46 g = 0.046 kg    (1 kg = 1000 g)

v = velocity

Now put all the given values in the above formula, we get:

K.E=\frac{1}{2}mv^2

6.8J=\frac{1}{2}\times 0.046kg\times v^2

6.8kg.m^2/s^2=\frac{1}{2}\times 0.046kg\times v^2

v=17.19m/s\approx 17m/s

Therefore, the ball's velocity be as it leaves the cannon is, 17 m/s

3 0
3 years ago
How are animals of the coniferous forest well adapted to long, cold winters?
skelet666 [1.2K]
They have thick body coverings
3 0
3 years ago
ATP molecules store cellular energy. When phosphate groups are removed and molecules of ADP are formed, energy is released. This
slava [35]
<span>Adenosine triphosphate (ATP) consists of an adenosine molecule bonded to three phophate groups in a row. In a process called cellular respiration, chemical energy in food is converted into chemical energy that the cell can use, and stores it in molecules of ATP. This occurs when a molecule of adenosine diphosphate (ADP) uses the energy released during cellular respiration to bond with a third phosphate group, becoming a molecule of ATP. So the energy from cellular respiration is stored in the bond between the 2nd and 3rd phosphate groups of ATP. When the cell needs energy to do work, ATP loses its 3rd phosphate group, releasing energy stored in the bond that the cell can use to do work. Now its back to being ADP and is ready to store the energy from respiration by bonding with a 3rd phosphate group. ADP and ATP constantly convert back and forth in this manner.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
3 0
3 years ago
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