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mojhsa [17]
3 years ago
11

How do I solve for horizontal force? And how can I find the acceleration to find the force? And how do I find the power during s

pecific intervals?

Physics
1 answer:
Snezhnost [94]3 years ago
5 0

Answer:hhmm c

Explanation:

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7. Calculations.
kotykmax [81]

Answer:

5 ms-2

Explanation:

F = ma

F = 100N

m = 20kg ( you should make sure the unit is kg before you answer the question)

100 = 20a

a = 100÷ 20

a = 5 ms-2

4 0
3 years ago
Why is force not on a scalar quantity??
snow_lady [41]
Because force always has a direction, it always works towards or against something.


you might know that force,
is rate of change of momentum i.e

force = m (v-u)/t
= (mv - mu )/ t


as we know momentum is a vector quantity so, the rate of change of momentum i.e Force would also be a vector quantity.




momentum = mass × velocity

velocity has a direction so,
momentum has also got a direction.
so, momentum is also a vector quantity.
3 0
3 years ago
Read 2 more answers
Vapor pressure is related to the temperature of the liquid. user: in an open system, the vapor pressure is equal to the _____. i
iVinArrow [24]

Answer

-Directly;  outside air pressure

Vapor pressure is directly related to the temperature of the liquid. user: in an open system, the vapor pressure is equal to the outside air pressure.

Explanation;

-As the temperature of a system increases, the average kinetic energy of the molecules increases in both the liquid and gas phases.

-A higher average kinetic energy facilitates the escape of molecules from the liquid phase into the gas phase. At the same time, the rate of return of gas phase molecules to the liquid also increases. A new equilibrium point is reached at a higher gaseous vapor pressure. The increase in vapor pressure with temperature is exponential.


6 0
3 years ago
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HELP PLS
melomori [17]

If the field is in a vacuum, the magnetic field is the dominant factor determining the motion. Since the magnetic force is perpendicular to the direction of travel, a charged particle follows a curved path in a magnetic field. The particle continues to follow this curved path until it forms a complete circle. Another way to look at this is that the magnetic force is always perpendicular to velocity, so that it does no work on the charged particle. The particle’s kinetic energy and speed thus remain constant. The direction of motion is affected but not the speed.

A negatively charged particle moves in the plane of the paper in a region where the magnetic field is perpendicular to the paper (represented by the small × ’s—like the tails of arrows). The magnetic force is perpendicular to the velocity, so velocity changes in direction but not magnitude. The result is uniform circular motion.

4 0
3 years ago
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A 3.0 kg box is sliding along a frictionless horizontal surface with a speed of 1.8 m/s when it encounters a spring. (a) Determi
krok68 [10]

Answer:

a) k = 2231.40 N/m

b) v = 0.491 m/s

Explanation:

Let k be the spring force constant , x be the compression displacement of the spring and v be the speed of the box.

when the box encounters the spring, all the energy of the box is kinetic energy:

the energy relationship between the box and the spring is given by:

1/2(m)×(v^2) = 1/2(k)×(x^2)

    (m)×(v^2) = (k)×(x^2)

a) (m)×(v^2) = (k)×(x^2)

                 k = [(m)×(v^2)]/(x^2)

                 k = [(3)×((1.8)^2)]/((6.6×10^-2)^2)

                 k = 2231.40 N/m

Therefore, the force spring constant is 2231.40 N/m

b) (m)×(v^2) = (k)×(x^2)

             v^2 = [(k)(x^2)]/m

                 v =  \sqrt{ [(k)(x^2)]/m}

                 v = \sqrt{ [(2231.40)((1.8×10^-2)^2)]/(3)}

                    = 0.491 m/s

8 0
2 years ago
Read 2 more answers
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