Answer:
The amount of water converted from liquid to gas with 6,768 joules is approximately 3.035 g
Explanation:
The amount of heat required to convert a given amount of liquid to gas at its boiling point is known as the latent heat of evaporation of the liquid
The latent heat of evaporation of water, Δ
≈ 2,230 J/g
The relationship between the heat supplied, 'Q', and the amount of water in grams, 'm', evaporated is given as follows
Q = m × Δ
Therefore, the amount of water, 'm', converted from liquid to gas at the boiling point temperature (100°C), when Q = 6,768 Joules, is given as follows;
6,768 J = m × 2,230 J/g
∴ m = 6,768 J /(2,230 J/g) ≈ 3.035 g
The amount of water converted from liquid to gas with 6,768 joules = m ≈ 3.035 g.
Sorry, the correct answer is A. 3.4 x 10 - 24
Hope I helped ; )
The answer is Heat energy moves from warmer objects to cooler ones
Answer:
2350kg of Al₂O₃
Explanation:
<u><em>Step 1 : Write the balanced chemical equation:</em></u>
4Al + 3O₂ → 2Al₂O₃
<u><em>Step 2: Find the Ratio of Al :</em></u> Al₂O₃
Al : Al₂O₃
4 : 2
2 : 1
4700: 2350
= 2350kg of Al₂O₃
The correct answer is D. Using the law of conservation of mass the number of atoms on each side of the equation should be equal. Through introspection, we find that there are 2
atoms on reactant side as opposed 3Cl atoms on product side. If we add a coefficient of 3 on 
we get
.
Now there are 6Cl atoms on reactant side and 2 on product side, hence we add a coefficient of 2 on both 
and 
. The balanced chemical equation is,
