Answer:
Explanation:
As we know that sound level is given as
so here we have
now we can take anti log both sides
so we have
so above is the expression for the intensity of sound in terms of reference intensity and sound level
Answer:
im not 100% sure but i think its the base of your big toe or the arch of your foot
Explanation:
thats how i do it
Answer:
Distance in pc= 20parsecs
Distance in zLY= 65.2LY
Distance in AU= 4.1×10^6AU
Explanation:
Using the formular:
d = 1/p
Where d = distance
P= parallax angle in arc of second
d= 1/0.050
d= 20 parsed
Converting to Lighy years,LY :
1 PC = 3.26LY
d= 20pc × (3.26Ly/1pc)
d= 65.2Ly
To convert to AU, 206,265 AU = 1pc
d= 20pc × (2.06×10^5AU/1pc)
d= 4.1×10^6AU
Question:
A cork floats on the surface of an incompressible liquid in a container exposed to atmospheric pressure. The container is then sealed and the air above the liquid is evacuated. The cork:
A. sinks slightly
B. rises slightly
C. floats at the same height
D. bobs up and down about its old position
Answer:
The correct answer is C) floats at the same height
Explanation:
The liquid is incompressible because its density very high and leaves no room for further compaction whether or not there is atmospheric pressure. So when you put a cork on the liquid, pressure or no pressure, there is no displacement hence it floats on the same height regardless of the absence of air.
Cheers!
Answer:
For mass m 1 newton 2nd law
F=m 1 a 1
5=m 1 ×10
m 1 = 2
1
kg
For mass m 2
F=m 2 a 2
5=m 2
×20
m 2
= 4
1 kg
if tied together
Total mass =m 1 +m 2 = 1/2 +1/4=3/4kg
Now
F=M
T Q
T
a T = 5/m T = 5×4/3 = 3
/20m/s^2
Explanation:
