Question

4. What is the electric field strength (E) at a distance of 0.50 m from a 1.00×10°C charge?

Answer 1

Answer:

3.6*10¹⁰N/C

Explanation:

The formula for Electric field strength is expressed as:

E = kQ/r²

k is the coulombs constant = 9*10^9Nm²/C²

Q is the charge = 1.00×10°C

r is the distance = 0.50m

Substitute the parameters into the formula as shown:

E = kQ/r²

E =  9*10^9(1)/0.5²

E =  9*10^9/0.25

E = 36*10^9

E = 3.6*10¹⁰N/C

Hence  the electric field strength is 3.6*10¹⁰N/C