Answer
given,
mass of crate = 32.5 Kg
horizontal force = 14 N
initial speed, u = 0 m/s
a) acceleration produced = ?
we know,
F = m a


a = 0.431 m/s²
b) using equation of motion
t = 10 s


s = 21.54 m
c) again using equation of motion
v = u + at
v = 0 + 0.431 x 10
v = 4.31 m/s
Answer:
C) three times slow than on earth
I showed my working in the images above. if you have any questions please feel free to ask
Travis Scott!3&;8284$28&:!;&29395
Answer:
A) The resultant force is 43.4 [N]
B) The movement of the heavy crate is going to the right and in the negative direction on the y-axis
Explanation:
We need to make a sketch of the different forces acting on the heavy crate.
In the attached image we can see the forces and the sum of the vector with their respective angles.
Forces in the X-axis

Forces in the y-axis
![FDiony=0[N]\\Fshirley= 16.5*sin(30)=8.25[N]\\Fjoany=19.5*sin(60)=16.88 [N]\\\\Forcesy=0+8.25-16.88= -8.63[N]](https://tex.z-dn.net/?f=FDiony%3D0%5BN%5D%5C%5CFshirley%3D%2016.5%2Asin%2830%29%3D8.25%5BN%5D%5C%5CFjoany%3D19.5%2Asin%2860%29%3D16.88%20%5BN%5D%5C%5C%5C%5CForcesy%3D0%2B8.25-16.88%3D%20-8.63%5BN%5D)
Using the Pythagorean theorem

The movement of the heavy crate is going to the right and in the negative direction on the y-axis, this can be easily seen in the graphical sum of vectors.