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horrorfan [7]
3 years ago
11

PLEASE HELP THIS IS DUE TODAY!! (GIVING BRAINLIEST TO WHOEVERY ANSWERS QUICKLY AND CORRECTLY!) 15 POINTS!

Physics
1 answer:
Jlenok [28]3 years ago
5 0

As the core collapses, the outer layers of the star are expelled. A planetary nebula is formed by the outer layers. The core remains as a white dwarf and eventually cools to become a black dwarf. ... Like low-mass stars, high-mass stars are born in nebulae and evolve and live in the Main Sequence

hydrogen shell burning - outer layers swell. Red Giant Branch - helium ash core compresses - increased hydrogen shell burning. First Dredge Up - expanding atmosphere cools star - stirs carbon, nitrogen and oxygen upward - star heats up.

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Explain why total internal reflection has make communication much faster through the use of fibre optic
Inessa05 [86]

Answer:

Due to total internal reflection lose of imformation is almost none in optic fibre. Less time is required to transmit the imformation.

Explanation:

7 0
3 years ago
Ways we can reducing Surface Tension<br>​
valina [46]

Surface tension can change with the change in a medium that is just above the layer of the liquid's surface.

Explanation:

Pouring any oil or oily compounds (such as kerosene) on the free surface of the water will reduce the surface tension.

in the atmosphere directly affects the surface tension of the liquid.

If we increase the temperature of the water, then there is a high possibility of the surface tension of the water getting reduced, due to the fact that the net force of attraction is decreased.

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8 0
2 years ago
Read 2 more answers
1. A boat initially moving at 10 m/s accelerates at 2 m/s2 for 10 s. What is the velocity of the boat after 10 seconds?​
DIA [1.3K]

Answer:

5 m/s is the answer so yeah

5 0
3 years ago
What is the relationship between the force and the period in a mass hanging on a spring oscillation and why?
BabaBlast [244]

Explanation:

Period of a mass on a spring is:

T = 2π√(m/k)

T is a function of only m and k.  So the period is independent of force.

5 0
3 years ago
A red laser from the physics lab is marked as producing 632.8-nm light. When light from this laser falls on two closely spaced s
BARSIC [14]

Answer:

The wavelength is  \lambda_R  =  649 *10^{-9}\ m

Explanation:

From the question we are told that

   The wavelength of the red laser is  \lambda_r  =  632.8 \ nm =  632.8 *10^{-9}\ m

    The spacing between  the fringe is  y_r  =  6.00\ mm =  6.00*10^{-3}  \  m

   The spacing between  the fringe for smaller laser point  is  y_R   = 6.19 \ mm =  6.19 *10^{-3} \  m

      Generally the spacing between  the fringe is mathematically represented as

       y  =  \frac{D *  \lambda  }{d}

Here  D is the distance to the screen

    and  d is the distance of the slit separation

Now for both laser red light light and  small laser  point  D and  d are same for this experiment

So

         \frac{y_r}{\lambda_r}  =  \frac{D}{d}

=>      \frac{y_r}{\lambda_r}  = \frac{y_R}{\lambda_R}

Where \lambda_R  is the wavelength produced by the small laser pointer

  So

           \frac{6.0 *10^{-3}}{ 632.8*10^{-9}}  = \frac{ 6.15 *10^{-9}}{\lambda_R}

=>       \lambda_R  =  649 *10^{-9}\ m

7 0
3 years ago
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