<h3>a. The impulse</h3>
The impulse is 100.0 Ns
The impulse I = Ft where
- F =average force = 50.0 N and
- t = time = 2.0 s
Substituting these values into the equation, we have
I = Ft
I = 50.0 N × 2.0 s
I = 100.0 Ns
The impulse is 100.0 Ns
<h3>b. Change in momentum</h3>
The change in momentum is 100 kgm/s
Since change in momentum Δp = I where I = impulse.
Since I = 100.0 Ns,
Substituting this into the equation, we have
Δp = I
= 100.0 Ns
= 100 kgm/s
The change in momentum is 100 kgm/s
<h3>c. Mass's change in velocity</h3>
The change in velocity is 25.0 m/s
Since change in momentum Δp = mΔv where
- m = mass = 4.0 kg and
- Δv = change in velocity.
Making Δv subject of the formula, we have
Δv = Δp/m
Substituting the values of the variables into the equation, we have
Δv = Δp/m
Δv = 100.0 kgm/s/4.0 kg
Δv = 25.0 m/s
The change in velocity is 25.0 m/s
Learn more about impulse here:
brainly.com/question/25700778
Answer:
Its speed is maximum and its acceleration is zero
Explanation:
- Concerning the speed:
In a simple harmonic motion, the speed can be determined through the law of conservation of energy. In fact, we have that the total mechanical energy of the system, which is sum of elastic potential energy U and kinetic energy K, is constant:
where k is the spring constant, x is the displacement, m is the mass and v is the speed.
We see that when the displacement is 0, x = 0: this means that the elastic potential energy U is also 0, therefore the kinetic energy K is maximum, and so the speed v is also maximum.
- Concerning the acceleration:
According to Newton's second law, the acceleration of the system is proportional to the net force:
the net force is just the restoring force of the spring, given by Hooke's law:
So, the acceleration is
and we see that when the displacement is zero, x = 0, and so the acceleration is also zero.
The equation of the wave travelling along the +x-axis is y = 0.02 sin (880π/330 x – 880 πt)
<u>Explanation:</u>
Given data
Amplitude 0.02 m , Frequency= 440 Hz ,Speed = 330 m/s
The equation format is written as,
y = A sin ( k x – ω t)
We need the value of A, k, x -ω t
<u>1. Find the k value</u>
v = f ×λ
330 = 440×λ
k = 2π×λ
k = 880 π /330 m-1
440 ×2π = w
<u>2. Find the ω value</u>
f×2π =ω
ω
= 880 π s-1
<u>3. Find the A value</u>
we get A value from the given data
A = 0.02 m
By the formula,
y = A sin ( k x – ω t)
Substitute the values we get the equation,
y = 0.02 sin (880π/330 x – 880 πt)
The equation of the wave travelling along the +x-axis is y = 0.02 sin (880π/330 x – 880 πt)
Answer:
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