Explanation:
a) F = GmM / r²
F = (6.67×10⁻¹¹) (500) (5.98×10²⁴) / (6.4×10⁶ + 1.5×10⁶)²
F = 3200 N
b) F = ma
3200 = 500a
a = 6.4 m/s²
c) a = v² / r
640 = v² / (6.4×10⁶ + 1.5×10⁶)
v = 7100 m/s
Answer:
Calorimeter is used to measure heat in and represents that in units of joules per kelvin units J/˚C or kJ/K
A calorimeter is can be used to measure the amount of heat released or involved in a chemical reaction.
Whereas thermometer can only measures temperature or hotness of a substance. It cannot be used to measure the thermal rate or amount of heat energy of a reaction. Unit measurement used by thermometer is Celsius (°C).
Explanation:
His kinetic energy is converted to potential energy.
Answer:
(B) 1.17 m.
Explanation:
At the highest point, the conservation of energy equation would becomes;
K.E (initial ) = K.E + P.E;
½ m(V)^2 = ½ m(V)^2 + mgh
(m*6^2)/2 = (m * 9.81 * 1.1) + (m*V^2)/2
36/2 = (9.81 * 1.1) + v^2/2
Solving the equation;
v=√14.44 m/s
= 3.8 m/s
a = −0.6g
= -0.6*9.81
= −5.88 m/s^2
Using equation of motion,
V^2 = U^2 + 2aS
S = V^2/2a
= 14.44/12
= 1.19 m.
Answer: A glob of very soft clay is dropped from above onto a digital scale. The clay sticks to the scale on impact. A graph of the clay's velocity vs. time, clay (t), is given, with the upward direction defined as positive.
The experiment is then repeated, but instead of using the clay glob, a superball with identical mass is dropped from the same height onto the scale.
Both the clay and the superball hit the scale 2.9s after they are dropped. Assume that the duration of the collision is the same in both cases and the force exerted by the scale on the clay and the force exerted by the scale on the superball are constant.
Explanation:
