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bonufazy [111]
3 years ago
8

Two objects have charges 2.0 C and 1.0 C. If the objects are placed 2 meters apart, what is the magnitude of the force that the

2 C object exerts on the 1 C obejct?

Physics
1 answer:
kondor19780726 [428]3 years ago
4 0

Answer:

4.5\cdot 10^9 N

Explanation:

The electric force between two charged objects is given by:

F=k\frac{q_1 q_2}{r^2}

where:

k is the Coulomb's constant

q1 and q2 are the charges of the two objects

r is their separation

In this problem:

q1 = 2.0 C

q2 = 1.0 C

r = 2 m

So, the electric force is

F=(9\cdot 10^9 Nm^2C^{-2})\frac{(2.0 C)(1.0 C)}{(2 m)^2}=4.5\cdot 10^9 N

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Answer:

\mathrm{v}_{2} \text { velocity after the collision is } 3.3 \mathrm{m} / \mathrm{s}

Explanation:

It says “Momentum before the collision is equal to momentum after the collision.” Elastic Collision formula is applied to calculate the mass or velocity of the elastic bodies.

m_{1} v_{1}=m_{2} v_{2}

\mathrm{m}_{1} \text { and } \mathrm{m}_{2} \text { are masses of the object }

\mathrm{v}_{1} \text { velocity before the collision }

\mathrm{v}_{2} \text { velocity after the collision }

\mathrm{m}_{1}=600 \mathrm{kg}

\mathrm{m}_{2}=900 \mathrm{kg}

\text { Velocity before the collision } v_{1}=5 \mathrm{m} / \mathrm{s}

600 \times 5=900 \times v_{2}

3000=900 \times v_{2}

\mathrm{v}_{2}=\frac{3000}{900}

\mathrm{v}_{2}=3.3 \mathrm{m} / \mathrm{s}

\mathrm{v}_{2} \text { velocity after the collision is } 3.3 \mathrm{m} / \mathrm{s}

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3 years ago
The boiling point of water at sea level is 100 °c. at higher altitudes, the boiling point of water will be
Scilla [17]
   <span> The boiling point of water at sea level is 100 °C. At higher altitudes, the boiling point of water will be.....
a) higher, because the altitude is greater.
b) lower, because temperatures are lower.
c) the same, because water always boils at 100 °C.
d) higher, because there are fewer water molecules in the air.
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What is the mass of a rock lifted 2 meters off the ground that has 196 J of potential energy?
eimsori [14]

Answer:

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Explanation:

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PE=196J

g(gravitational force)=9.8m/s^2

h(change in height)=2m

m=?

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3 years ago
Help :((((((((((((((((((((
Ann [662]

3-6 seconds time interval is the object slowing down.

The correct option is C.

<h3>What is a time interval?</h3>

The time interval is the span of time among two specified times. To put it another way, it is the amount of time that has passed between the event's start and finish.

<h3>What are different time intervals?</h3>

The time interval is the length of time that the aim uses to gather data and determine values. The critical overview can be one or more seconds, minutes, hours, days, weeks, or months. The period must be greater than zero and positive. When providing minutes, the amount of minutes must divide evenly by 60.

To know more about Time interval visit:

brainly.com/question/28238258

#SPJ13

The complete question is -

During which time interval is the object slowing down ?

a- 8-10 seconds

b- 6-8 seconds

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DaniilM [7]

Answer:

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Explanation:

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