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Jobisdone [24]
3 years ago
5

Write the equation of the line that has an undefined slope and passes through the point (4, 7). User: What is the slope of a lin

e that is parallel to the x-axis? User: What is the slope of the line that passes through the points (-3, 5) and (1, 7)? User: Which of the following equations is the translation 2 units left of the graph of y = |x|?
Physics
2 answers:
DerKrebs [107]3 years ago
6 0
<u>For the first question we use point-slope form of an equation</u>

y-y_{1}=m(x-x_{1})
y=m(x-x_{1})+y_{1}

then we plug in the known values

y=m(x-4)+7

we leave the slope as variable m since it is undefined

<u>For Question 2
</u>
A line that is parallel to the x-axis is a horizontal line and since the slope of a line is defined as the Δy/Δx (change in y/change in x) and the change in y is 0 at any 2 points observed on the line the slope is 0. (0/any number is 0)

<u>For Question 3
</u>
Following the same relationship as question 2 we can solve for the slope.

Δy/Δx
y_{1}-y _{2}/x_{1}-x_{2}

now we plug in the known values from the two points given

(5-7)/(-3-1)
-2/-4
m=1/2 or 0.5

<u><em>and For the Final Question</em></u>

a translation left or right is done by affecting the x variable if you add 2 to x then the x value will have to be 2 less to get the same result...in other words when x is 1 the value of y is also 1...but if I wanted the whole equation translated left 2 unites then I would want the same y-value at an x-value 2 smaller... in other words, in our example x will be -1 when y is 1. For this value found on the graph to match the equation our x value must have 2 added to it in the equation....therefore the equation that translates y=|x| two units left is...

y=|x+2| 



Brrunno [24]3 years ago
4 0

1.

Answer:

y = m(x - 4) + 7

Explanation:

as we know that equation of straight line passing through a fixed point and having undefined slope is given as

y - y_1 = m(x - x_1)

here we have

(x_1, y_1) = (4, 7)

so we will have

y - 7 = m(x - 4)

y = m(x - 4) + 7

2.

Answer:

slope = ZERO

Explanation:

Slope of the straight line is defined as the tangent of the angle made by the line with respect to x axis

here we need to find the slope of a straight line parallel to x axis so the angle is ZERO degree

hence the slope will be given as

m = tan 0

m = 0

3.

Answer:

m = 0.5

Explanation:

Slope of a straight line passing through two different points is given as

m = \frac{y_2 - y_1}{x_2 - x_1}

here we will have

m = \frac{7 - 5}{1 + 3}

m = \frac{2}{4}

m = 0.5

4.

Answer:

y = |x - x'|

here x' = any positive number

Explanation:

If we translate the graph 2 units left of the given position so we can say that we have shifted the graph above from its given position.

So we will have

y = |x - x'|

here x' = any positive number

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(b) The distance of mass from mass A if there is no gravitational force acted on C
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Answer:

(a) The force, acting on object 'C' is approximately 2.66972 × 10⁻¹⁰ Newtons

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Explanation:

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The distance between particle 'A' and particle 'B', r₁ = 0.15 m

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(a) The gravitational force, 'F', is given as follows;

F =G \times \dfrac{m_{1} \times m_{2}}{r^{2}}

Where;

F = The force between the two masses

G = The gravitation constant = 6.67430 × 10⁻¹¹ N·m²/kg²

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If 'C' is placed at 0.05 m from 'B', we have;

F₂₃ =  6.67430 × 10⁻¹¹ × 0.05 × 0.3/(0.05²) ≈ 4.00458 × 10⁻¹⁰

The gravitational force between force between particle 'B' and particle 'C', F₂₃ = 4.00458 × 10⁻¹⁰ N (towards the right)

F₁₃ =  6.67430 × 10⁻¹¹ × 0.05 × 2/(0.1²) ≈ × 10⁻¹⁰

The gravitational force between force between particle 'A' and particle 'B', F₁₃ = 6.6743 × 10⁻¹⁰ N (towards the left)

The force, 'F', acting on object 'C' = F₁₃ - F₂₃

F = (6.6743 - 4.00458) × 10⁻¹⁰ = 2.66972 × 10⁻¹⁰ N

The force, acting on object 'C' ≈ 2.66972 × 10⁻¹⁰ N

(b), When there is no gravitational force acting on 'C', let the distance of 'C' from 'A' = x

We have;

F₂₃ = F₁₂

F_{23} =G \times \dfrac{m_{1} \times m_{2}}{r_1^{2}} = F_{13} =G \times \dfrac{m_{1} \times m_{3}}{r_2^{2}}

By plugging in the values and removing like terms, we get;

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(1.15 - x)² × 2 × 0.05 = 0.3 × 0.05 × x²

0.1·x² - 0.23·x + 1.3225 = 0.015·x²

0.1·x² - 0.23·x + 1.3225 - 0.015·x² = 0

0.085·x² - 0.23·x + 0.13225= 0

x = (0.23± √((-0.23)² - 4 × 0.085 × ( 0.13225)))/(2 × 0.085))

x ≈ 0.829, or x ≈ 1.877

Therefore, the distance of 'C' from 'A', if there is no gravitational force acting on 'C', x ≈ 0.829 m, or x = 1.877 m, in the direction of 'B'

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