Answer:
833kg/m³
Explanation:
We have volume as Vm³
Density of this object = dKg/m³
Water density = 1000kg/m³
g = 10m/s²
We calculate FB which is the the buoyant force on object. Calculated as volume of object multiplied by water density
Fb = 1000Vg upwards
W = Vdg
Acceleration = net upwards/m
M = mass
2 = (1000g-gd)/d
2d = 10000 - 10d
2d + 10d = 10000
12d = 10000
d = 833.33kg/m³
Approximately 833kg/m³
The average density of the object is therefore 833kg/m³
Answer:
public class Window extends DesktopComponent {
public Window() {super("Window");}
public void onClicked() {System.out.println("Window selected");}
}
Explanation:
Answer:
A. 2.83 m/s
B. 39.55 degrees north of east
Explanation:
The velocity of the ball relative to the ground is the sum vectors of velocity of the ball relative to Mia and the velocity of Mia relative to the ground
If we take north east as positive direction then
Velocity vector of the ball relative to Mia is
![= =](https://tex.z-dn.net/?f=%3C3.6%20sin30%5E0%2C%20-3.6cos%2030%5E0%20%3E%20%3D%20%3C3.6%20%2A%201%2F2%2C%20-3.6%20%2A0.866%3E%20%3D%20%3C1.8%2C%20-3.12%3E)
Velocity of Mia relative to gorund is
<0, 5.3>
So velocity of the ball relative to the ground is
<1.8, -3.12> + <0, 5.3> = <1.8, 2.18>
Its magnitude is:
m/s
Its direction is
north of east
Answer:
F = 2.26 × 10⁻³ N
Explanation:
given,
length of rod = 11 cm
charge = 19 nC
linear charge density = 3.9 x 10⁻⁷ C/m
electric force at 2 cm away.
![E(r) = \dfrac{2K\lambda}{r}](https://tex.z-dn.net/?f=E%28r%29%20%3D%20%5Cdfrac%7B2K%5Clambda%7D%7Br%7D)
F = E q
![F= \dfrac{2K\lambda\ q}{L}\int \dfrac{dr}{r}](https://tex.z-dn.net/?f=F%3D%20%5Cdfrac%7B2K%5Clambda%5C%20q%7D%7BL%7D%5Cint%20%5Cdfrac%7Bdr%7D%7Br%7D)
integrating from 0.02 to 0.02 + L
![F= \dfrac{2K\lambda\ q}{L}[ln(0.02+L)-ln(0.002)]](https://tex.z-dn.net/?f=F%3D%20%5Cdfrac%7B2K%5Clambda%5C%20q%7D%7BL%7D%5Bln%280.02%2BL%29-ln%280.002%29%5D)
![F= \dfrac{2\times 9 \times 10^9\times 3.9\times 10^{-7}\times 19 \times 10^{-9}}{0.11}[ln(0.02+0.11)-ln(0.002)]](https://tex.z-dn.net/?f=F%3D%20%5Cdfrac%7B2%5Ctimes%209%20%5Ctimes%2010%5E9%5Ctimes%203.9%5Ctimes%2010%5E%7B-7%7D%5Ctimes%2019%20%5Ctimes%2010%5E%7B-9%7D%7D%7B0.11%7D%5Bln%280.02%2B0.11%29-ln%280.002%29%5D)
F = 2.26 × 10⁻³ N