Answer: One: <u>Selenium</u> is ParamagneticExplanation: Those compounds which have unpaired electrons are attracted towards magnet. This property is called as paramagnetism. Lets see why remaining are not paramagnetic.Electronic configuration of Scandium; Sc = 21 = 1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹ Sc³⁺ = 1s², 2s², 2p⁶, 3s², 3p⁶ Hence in Sc³⁺ there is no unpaired electron.Electronic configuration of Bromine; Br = 35 = 1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁵ Br⁻ = 1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶ Hence in Br⁻ there is no unpaired electron.Electronic configuration of Magnesium; Mg = 12 = 1s², 2s², 2p⁶, 3s² Mg²⁺ = 1s², 2s², 2p⁶ Hence in Mg²⁺ there is no unpaired electron.Electronic configuration of selenium; Se = 34 = 1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁴ Or, Se = 34 = 1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4px², 4py¹, 4pz¹ Hence in Se there are two unpaired electrons hence it is paramagnetic in nature.