Ask question

Ask question

All categories

3 years ago

12

6. An aircraft is is travelling along a runway at a Velocity of 25m/s in It accelerates at a rate of 4m/s² for a distance of 750

m before taking off.
Calculate its take-off speed

1 answer:

zysi [14]3 years ago

7 0

Answer:

Take-off velocity = v = 81.39[m/s]

Explanation:

We can calculate the takeoff speed easily, using the following kinematic equation.

$v_{f}^{2}=v_{i}^{2} +2*a*x$

where:

a = acceleration = 4[m/s^2]

x = distance = 750[m]

vi = initial velocity = 25 [m/s]

vf = final velocity

$v_{f}=\sqrt{(25)^{2}+(2*4*750) } \\v_{f}=81.39[m/s]$

You might be interested in

Which scientist contributed to disproving spontaneous generation?

kompoz [17]

Answer:

A. John Tyndall

Explanation:

In 1887, John Tyndall confirmed the theory of <u>biogenesis</u>, formulated by Luis Pasteur in 1864, applying sterilization by <u>discontinuous heating</u>, a process that is currently known as tyndalization. Evidence of the existence of resting microbacterial forms, very resistant to heat.

Thanks to this demonstration he is recognized as the <em>father of microbiology</em> with Pasteur. The theory brought down the previous idea of the Spontaneous Generation, which remained in force since 1745.

5 0

3 years ago

Anti-reflective coatings on lenses use thin-film interference to eliminate the reflection of a particular color. Suppose a glass

Sidana [21]

Answer with Explanation:

We are given that

$n_g=1.55$

$n_f=1.35$

$\lambda=521 nm=521\times 10^{-9} m$

$1 nm=10^{-9} m$

a.We have to find the expression for the minimum thickness the film can have ,t.

Condition for destructive interference

$2nt=(m+\frac{1}{2})\lambda$

$t=\frac{(m+\frac{1}{2})\lambda}{2n}$

For minimum thickness m=0

Then, $t=\frac{\lambda}{4n}$

b.Substitute the values

$t=\frac{521\times 10^{-9}}{4\times 1.35}=96.5nm$

7 0

3 years ago

A person runs 2 laps around a 400 meter track and stops where they initially

nalin [4]

The runner's total distance covered was 800 meters. Her displacement (straight-line distance between start-point and end-point) was zero.

Her average speed = (distance)/(time) = 4.04 m/s

Her average <em>velocity</em> = (displacement) / (time) = <em>zero (choice - c)</em>

5 0

3 years ago

Metric conversions

AfilCa [17]

<h3>1:-</h3>

1m=10dm

$\\ \sf\longmapsto 15m$

$\\ \sf\longmapsto 15(10)$

$\\ \sf\longmapsto 150dm$

<h3>2:-</h3>

1L=1000cm^3

$\\ \sf\longmapsto 0.023cm^3$

$\\ \sf\longmapsto 0.023\times 0.001$

$\\ \sf\longmapsto 0.00023L$

<h3>3:-</h3>

1km=1000m

$\\ \sf\longmapsto 0.00049km$

$\\ \sf\longmapsto 0.00049(1000)$

$\\ \sf\longmapsto 0.49m$

4:-

1kg=1000g

$\\ \sf\longmapsto 0.25kg$

$\\ \sf\longmapsto 0.25(1000)$

$\\ \sf\longmapsto 250g$

5:-

1g=0.0001hg

$\\ \sf\longmapsto 15g$

$\\ \sf\longmapsto 15(0.0001)$

$\\ \sf\longmapsto 0.0015hg$

5 0

3 years ago

two pulleys one with adius 2 inches and the other with radius 8 inches are connected by a belt. If the 2 inch pulley is caused t

White raven [17]

Explanation:

we know that,

linear speed = circumference × revolution per minute

linear speed of belt = 2πr × revolution per minute

now we will compute the linear speed of a belt for 2 inch pulley that is,

linear speed for 2 inch pulley = (2π×2)×( 3 revolutions per minute) ∵ r =2

= 4π × 3 revolution per minute (1)

again we will compute the linear speed of a belt for 8 inch pulley,

linear speed of 8 inch pulley = (2π×8) × (x revolution per minute) ∵ r =8

= 16π×x revolutions per minute (2)

As the linear speed is same for both pulleys. by comparing equations (1) and (2).

4π×3 = 16π×x

x = 3/4

Thus, the revolutions per minute for the 8 inch pulley is 3/4.

6 0

3 years ago