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Ivenika [448]
4 years ago
9

Plrase help a little stuck here

Physics
1 answer:
kkurt [141]4 years ago
7 0
(I'm lucky to have a computer ... It was only through the miracle of
modern digital technology that I was able to flip your photo right-
side-up to where I could read it.)

Here's how to figure out things like this:

The circle on the left side labeled ' <em>G</em> ' is the <em><u>G</u></em>enerator or battery
that powers this whole circuit and all the devices in it.  In order for
any device to work, you need to be able to set your pencil down at
the top of the Generator, and find a path through the circuit and
through that device, where current can flow all the way around to
the bottom of the Generator.  If you ever come to an open switch,
then current stops there, and you have to find another way through. 
If the path you found takes you back to the bottom of the generator but
it doesn't go through one of the devices, then that device doesn't work.

Look at the picture.  If you open switch  S-4, then Device-4 can't work,
because current can't go through it from one end of the Generator to
the other end.  But all of the other devices still work.

I can see  2  ways to turn off Device-3 with a single switch ... either
open switch S-5, or else open switch S-1.  Unfortunately, I think
either way will shut off all 5 devices.
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You have 100 grams of different substances, the most dense substance would have which volume? A. 1L B. 0.10 L. C. 100 L D. 10 L
guajiro [1.7K]
<span>Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. We do as follows:

</span><span>A. 1L
100 g /1L = 100 g/L

B. 0.10 L.
100g/0.10L = 1000 g/L ------> MOST DENSE SUBSTANCE

C. 100 L
</span>100g/100L = 1 g / L <span>

D. 10 L
</span>100g/10L = 10 g/L
6 0
3 years ago
Which kind of friction requires more force to overcome rolling or sliding fricton?
ANTONII [103]
Sliding friction is harder to overcome, and steals
more energy whenever you're moving.

That's why we switched from sleds to wheels
several thousand years ago.
8 0
3 years ago
I need help on 1. B and show work
Nata [24]
Acceleration = (end speed minus beginning speed) divided by (time for the change).
4 0
4 years ago
How might the daily activities of a scientist studying the stars differ from a chemist, physicist, or biologist?
VashaNatasha [74]

Answer:

look at explanation

Explanation:

Chemist studies chemicals

A physciats studies physicals things

a biologst studies biology

and these are their jobs!!

5 0
3 years ago
A uniform disk is constrained to rotate about an axis passing through its center and perpendicular to the plane of the disk. If
katrin2010 [14]

A uniform disk is constrained to rotate about an axis passing through its center and perpendicular to the plane of the disk. If the disk starts from rest and is then brought in contact with a spinning rubber wheel, we observe that the disk gradually begins to rotate too. If after 35 s of contact with this spinning rubber wheel, the disk has an angular velocity of 4.0 rad/s, find the average angular acceleration that the disk experiences. (Assume the positive direction is in the initial direction of rotation of the disk. Indicate the direction with the sign of your answer.)

Assume after 35 s of contact with this spinning rubber wheel, the disk has an angular velocity of 11.0 rad/s.

Answer:

385 rad

Explanation:

The expression for the angular acceleration of a disk that is in contact with a spinning wheel can be given as:

\alpha = \frac{\delta \omega}{\delta t}

where \delta\omega = \omega_f - \omega_i

\alpha = \frac{ \omega_f-\omega_i}{\delta t}

\alpha = \frac{ 4.0 rad/s-0 rad/s}{35}

\alpha =0.14 rad/s^2

Angular displacement of a disk can be calculated by using the formula:

\theta = \omega t

substituting 11.0 rad/s for \omega and t = 35 s ; we have:

\theta = 11.0 rad/s * 35 s

\theta = 385 rad

4 0
3 years ago
Read 2 more answers
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