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frosja888 [35]
3 years ago
13

Solve the equation 1 + 5x - 10 = 7x - 9 - 2x

Mathematics
1 answer:
Tom [10]3 years ago
6 0
<span>All real numbers are solutions.

</span>
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What is the slope of this graph?
scoray [572]

Answer:

2/3

Step-by-step explanation:

Hope this helps you

3 0
3 years ago
Pioneer company has given an aptitude test to 71 potential job applicants. The test score had an average of 81 and a standard de
Agata [3.3K]

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

In point A:

\to df = n - 1 = 71-1= 70

In point B:

\to t = \frac{(x -X)}{s} = \frac{(93-81)}{8} = \frac{12}{8}= 1.5

In point C:

For df = 70, the top 5% critical t score

tcrit = 1.666914479

Thus,

\to 1.666914479 = \frac{(x - 81)}{8}\\\\\to 1.666914479 \times 8 = (x - 81)\\\\\to  13.335315832 = (x - 81)\\\\\to  13.335315832 +81 =x \\\\\to x= 94.335315832

In point D:

For df = 70, the top 5% critical t score

tcrit = -1.666914479

\to -1.666914479 = \frac{(x - 81)}{8}\\\\\to -1.666914479 \times 8= (x - 81)\\\\\to -13.335315832= (x - 81)\\\\\to -13.335315832+81 = x \\\\\to x = 67.664684168\\\\

In point E:

The lower cutoff is 0.10 in the center, which would be around 80 %. The critical point therefore is

tcrit = -1.293762898

\to -1.293762898 = \frac{(x-81)}{8}\\\\\to -1.293762898 \times 8= (x-81) \\\\\to -1.293762898 \times 8= (x-81) \\\\\to -10.350103184=x-81\\\\\to -10.350103184+81=x\\\\\to x=70.649896816

In point F:

The lower cutoff is 0.90 in the center, which would be around 80 %. The critical point therefore is

tcrit = 1.293762898

\to 1.293762898 = \frac{(x-81)}{8}\\\\\to 1.293762898 \times 8= x-81\\\\\to 10.350103184 =x-81\\\\\to 10.350103184 +81=x\\\\\to x = 91.350103184\\

5 0
3 years ago
Solve the equation.
Natasha2012 [34]
I hope this helps you

4 0
3 years ago
Read 2 more answers
Jon drove 96 kilometers. How many miles did Jon drive (1 mile = 1.6 kilometers)?
dolphi86 [110]

Answer:

59.6

Step-by-step explanation:

8 0
4 years ago
An inlet pipe can fill an artificial pond in 70 min. An outlet pipe can empty the same pond in 200 min. With both pipes open, ho
vivado [14]

It takes 107.692 minutes approximately to fill the pond

<em><u>Solution:</u></em>

Given that inlet pipe can fill an artificial pond in 70 min

So the inlet pipe can fill \frac{1}{70} of the pond in 1 min

An outlet pipe can empty the same pond in 200 min

So the outlet pipe can empty \frac{-1}{200} of pond in 1 min

Here negative sign denotes "empties the pond"

To find: With both pipe open, time taken to fill the pond

Let "x" be the time taken by pipes to fill the pond

With both pipes are left on, so together their rate is:

\frac{1}{x} = \frac{1}{70} - \frac{1}{200}

On solving,

\frac{1}{x} = \frac{200 - 70}{14000}\\\\\frac{1}{x} = \frac{130}{14000}\\\\x = \frac{14000}{130} = 107.692

Thus it takes 107.692 minutes approximately to fill the pond

5 0
3 years ago
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