Ask question

Ask question

All categories

3 years ago

13

When bonding atoms seek to achieve a stable

1 answer:

Ronch [10]3 years ago

6 0

Answer:

a stable octet state

Explanation:

a stable octet state is when all the energy levels of the atoms are filled with electrons and they are stabe

You might be interested in

What is the total volume occupied by 132 g of CO2 at STP

Lilit [14]

132 grams x (1 mol / 44 grams) = 3 moles
<span>3 moles X (22.4 L/ 1 mol) = 67.2 </span><span>L</span>

4 0

3 years ago

Read 2 more answers

As the amount of salt in water increases, the___________ of the water increases.

Gnom [1K]

Answer:

3

Explanation:

5 0

3 years ago

Read 2 more answers

Difference between pure and applied research

nata0808 [166]

Answer:

pure is water made by us

Explanation:

lap water are pured also but somtimes they are dirty

6 0

3 years ago

Read 2 more answers

A standard drink of beer is _ ounces.

kiruha [24]

A standard drink of beer is 12 ounces

4 0

3 years ago

Read 2 more answers

GaryK [48]

<u>Answer:</u>

The percent composition of this compound is 94%

<u>Explanation:</u>

The reaction can be formed as

$2 \mathrm{Fe}+3 \mathrm{Cl}_{2} \rightarrow 2 \mathrm{FeCl}_{3}$

$\frac{\text { Weight of } \mathrm{Cl}_{2}}{\text { 3* Molar Mass of } \mathrm{Cl}_{2}}=\frac{\text { Weight of } \mathrm{Fe}}{2 * \text { Molar Mass of Fe }}$

$\frac{\text { Weight of } \mathrm{Cl}_{2}}{3 *(2 * 35.5)}=\frac{3.56}{2 * 55.8}$

$\text { Weight of } C l_{2}=\frac{3.56 * 3 * 71}{2 * 55.8}=6.79 \mathrm{g}$

$\mathrm{n}\left(\mathrm{Cl}_{2}\right)=\mathrm{m}\left(\mathrm{Cl}_{2}\right) / \mathrm{M}\left(\mathrm{Cl}_{2}\right)=6.79 / 71=0.1 \mathrm{m}$

$\mathrm{n}(\mathrm{Fe})=\mathrm{m}(\mathrm{Fe}) / \mathrm{M}(\mathrm{Fe})=3.56 / 55.8=0.06 \mathrm{m}$

Based on no. of iron reacted,

$\mathrm{n}(\text { moles of } \mathrm{Fe})=\mathrm{n}\left(\text { moles of } \mathrm{FeCl}_{3}\right)$

n = m/M

$\mathrm{m}\left(\mathrm{FeCl}_{3}\right)=\mathrm{n}^{*} \mathrm{M}=0.06^{*} 162.5=9.75 \mathrm{g}$

% composition of $FeCl_3$

= $(9.75 / 10.39)^{*} 100$

= 94%

6 0

3 years ago