When CH₄ is burnt in excess O₂ following products are formed,
CH₄ + 2 O₂ → CO₂ + 2 H₂O
According to equation 1 mole of CH₄ (16 g) reacts with 2 moles of O₂ to produce 1 mole of CO₂ and 2 moles of H₂O. Hence the products are,
1 mole of CO₂ and 2 moles of H₂O
Converting 1 mole CO₂ to grams;
As,
Mass = Moles × M.mass
Mass = 1 mol × 44 g.mol⁻¹
Mass = 40 g of CO₂
Converting 2 moles of H₂O to grams,
Mass = 2 mol × 18 g.mol⁻¹
Mass = 36 g of H₂O
Total grams of products;
Mass of CO₂ = 44 g
+ Mass of H₂O = 36 g
-------------
Total = 80 g of Product
Result:
80 grams of product is formed when 16 grams of CH₄ is burnt in excess of Oxygen.
Except catalyst because catalyst typically speed up a reaction by reducing the activation energy or changing the reaction mechanism.
[Kr] 4d10 5s2 5p4 is the noble gas configuration for telleurium because of the presence of different number of electrons.
<h3>What is telleurium?</h3>
Tellurium is a noble gas element that is non-reactive in nature due to complete outermost shell. It has atomic number of 52 which means that it has 52 number of electrons.
So we can conclude that [Kr] 4d10 5s2 5p4 is the noble gas configuration for telleurium because of the presence of different number of electrons.
Learn more about noble gas here: brainly.com/question/13715159
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Answer:
Heating a substance increases the speed at which molecules move.
Explanation:
Displacement is the distance and direction of an object's change in position from the starting.
Hence option B is correct.
Hope this helps!
