3:6:2 is the correct answer
Answer:
Explanation:
2AgNO₃ + Sn ⇄ Sn( NO₃)₂ + 2Ag
Ag⁺/Ag = .80 V
Sn⁺²/Sn = - .14 V
Hence Ag will be reduced and Sn will be oxidised . Hence the reaction will take place . YES .
2 ) 2 electrons are transferred .
3 )
2Ag⁺ + 2e = 2Ag
Sn = Sn⁺² + 2e
---------------------------
2Ag⁺ + Sn = Sn⁺² + 2Ag .
Answer: circle graph.
Justification:
A circle graph (also known as pie chart) is excellent to visualize the relative size of different sectors. Being the entire circle 100%, each sector will show the percent of each category.
In the given example, the circle will be divided in 3 different sectors, in which the size is proportional to the percent of each one.
In the given case::
<span>pH less than 8: 20%
</span><span>
</span><span> pH between 8 and 8.5: 50%,
</span><span>
</span><span>pH greater than 8.5: 30%
</span><span>
</span><span>
</span><span>So, a sector whose area is 20% will represent the first category, a sector whose area is 50% will represent the second category, and a sector whose area is 30% will represent the third category. The whole circle is 100%, this is the sum of the 3 categories is 100%.
</span>
This problem is providing us with the mass and density of a sample of liquid magnesium as 0.015 g and 1.738 g/cm³, respectively. Thus the volume, in microliters, of this same is required and found to be 8.63 μL according to the following calculations:
<h3>Density:</h3>
In science, density is defined as the degree of compactness of a substance and is calculated with:
![\rho =\frac{m}{V}](https://tex.z-dn.net/?f=%5Crho%20%3D%5Cfrac%7Bm%7D%7BV%7D%20)
Thus, given both the mass and density, we can solve for the volume as shown below:
![V=\frac{m}{\rho }](https://tex.z-dn.net/?f=V%3D%5Cfrac%7Bm%7D%7B%5Crho%20%7D%20)
By plugging in, we obtain the answer in cm³ first:
![V=\frac{0.015g}{1.738g/cm^3} =0.0086cm^3](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B0.015g%7D%7B1.738g%2Fcm%5E3%7D%20%3D0.0086cm%5E3)
Then, we convert it to microliters as follows:
![0.0086cm^3*\frac{1L}{1000cm^3} *\frac{1x10^6\mu L}{1L}=8.63\mu L](https://tex.z-dn.net/?f=0.0086cm%5E3%2A%5Cfrac%7B1L%7D%7B1000cm%5E3%7D%20%2A%5Cfrac%7B1x10%5E6%5Cmu%20L%7D%7B1L%7D%3D8.63%5Cmu%20L%20)
Learn more about density: brainly.com/question/952755
Answer:
The formulas that will be used are:
Situation one:
The moon will be experiencing gravitational force in the form of centripetal force, so we equate the two formulas.
Gravitational force = GMm /r²
Centripetal force = mv²/r
Equating,
GMm/r² = mv²/r
v² = GM/r
The first scenario will use the formula v² = GM/r
Situation 2:
The second situation will use the simple distance over time formula for velocity, where the distance will be the circumference and the time will be in seconds.
v = 2rπ/t
Explanation: