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KonstantinChe [14]
3 years ago
5

What’s the answer to this science problem?

Chemistry
1 answer:
Law Incorporation [45]3 years ago
5 0

Answer:

The image is not accurate because

the heavier atoms are moving faster than the lighter ones

but the lighter ones must move faster than the heavier ones.

Explanation:

The image depicts the atoms of two different elements; atoms of lighter and heavier elements.

And the rate of diffusion (movement of atoms) of an element is inversely proportional to the square root of its molecular.

⇒ As the weight increases, the rate of diffusion (movement of atoms) decreases.

And as the weight decreases, the rate of diffusion (movement of atoms) increases.

so, heavier atoms move slowly compared to lighter atoms.

The image is not accurate because

the heavier atoms are moving faster than the lighter ones

but the lighter ones must move faster than the heavier ones.

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A sample of gas has a volume of 20.0 mL at STP. What will the volume be if the temperature is changed to 546 K and the pressure
Ostrovityanka [42]

The volume did not change, it remained at 20 ml

<h3>Further explanation</h3>

Given

20 ml a sample gas at STP(273 K, 1 atm)

T₂=546 K

P₂=2 atm

Required

The volume

Solution

Combined gas Law :

\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}

Input the value :

\tt \dfrac{1\times 20}{273}=\dfrac{2\times V_2}{546}\\\\V_2=\dfrac{1\times 20\times 546}{273\times 2}\\\\V_2=20~ml

The volume does not change because the pressure and temperature are increased by the same ratio as the initial conditions (to 2x)

5 0
3 years ago
The decomposition of N2O to N2 and O2 is a first-order reaction. At 730°C, the rate constant of the reaction is 1.94 × 10-4 min-
grin007 [14]

Answer:

Total pressure 5.875 atm

Explanation:

The equation for above decomposition is

2N_2O \rightarrow 2N_2 + O_2

rate constant k =  1.94\times 10^{-4} min^{-1}

Half life t_{1/2} = \frac{0.693}{k} = 3572 min

Initial pressure N_2 O = 4.70 atm

Pressure after 3572 min = P

According to first order kinematics

k = \frac{1}{t} ln\frac{4.70}{P}

1.94\times 10^{-4} = \frac{1}{3572} \frac{4.70}{P}

solving for P we get

P = 2.35 atm

2N_2O \rightarrow 2N_2 + O_2

initial           4.70                         0             0

change        -2x                          +2x           +x

final             4.70 -2x                     2x           x

pressure ofO_2 after first half life  = 2.35 = 4.70 - 2x

                                                          x = 1.175

pressure of N_2 after first half life  =  2x = 2(1.175) = 2.35 ATM

Total pressure  = 2.35 + 2.35 + 1.175

                          = 5.875 atm

5 0
3 years ago
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Which statement below best describes the current model of the atom based on Rutherford’s gold foil experiment?
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Answer:

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One important sugar that results from photosynthesis is cellulose. True or false
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