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ololo11 [35]
4 years ago
8

As a snowboarder descends a mountain slope, gravity, the normal force, and friction combine to exert a net force of 320 N in the

downhill direction. The net force does 4700 J of work on her during one segment of her descent. If her path cuts across the face of the mountain at a 65 degree angle from the direction of the net force, over what distance does she travel.
Physics
1 answer:
Elis [28]4 years ago
3 0

Answer:

34.75m

Explanation:

Parameters given:

Net force, F = 320N

Work done by net force, W = 4700 N

Angle, θ = 65º

Work done at an angle is given as:

W = F * d * cosθ

Where d = distance travelled

θ is the angle between the force and the direction of motion.

Therefore,

4700 = 320 * d * cos65

=> d = 4700/(320 * cos65)

d = 34.75 m

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Answer and Explanation:

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7 0
3 years ago
Imagine you use Nitrogen as your gas. If you have the cold side as cold as you can without liquefying it (78 K), and run the hot
alina1380 [7]

Answer:

The efficiency of a Stirling engine is 74%

Explanation:

Given:

Temperature of gas when it is cold T_{1} = 78 K

Temperature of gas when it is hot T_{2} = 300 K

The efficiency of a stirling engine,

  \eta =1 - \frac{T_{1} }{T_{2} }

  \eta = 1- \frac{78}{300}

  \eta = 1-0.26

  \eta = 0.74

∴ \eta = 74 \%

Therefore, the efficiency of a Stirling engine is 74%

5 0
3 years ago
Suppose high tide is at midnight, the water level at midnight is 3 m, and the water level at low tide is 0.5 m. Assuming the nex
aev [14]

We have that the time, to the nearest minute, when the water level is at 1.125 m for the second time after midnight is

t=10.0hours

From the Question we are told that

Maximum height h_{max}=3m

Minimum height  H_{min}=0.5m

Time for  next high tide will occurT=12 hours =>720 min

Generally Average Height

h_{avg}=\frac{3+0.5}{2}\\\\h_{avg}=1.75

Therefore determine Amplitude to be

A=h_{max}=j_{avg}\\\\A=3-1.75\\\\A=1.25

Generally, the equation for Time is mathematically given by

At t=0

h(x)=Acos(Bx)+h_{avg}

Where

B=\frac{2\pi}{P}\\\\B=\frac{2\pi}{720}\\\\B=8.73*10^{-3}

Therefore

h(t)=Acos8.73*10^{-3}(t)+h_{avg}

Hence the Time at T=1.125 is

1.125(t)=1.25cos(8.73*10^{-3})(t)+1.75

-0.1249t=1.75

t=10.0hours

For more information on this visit

brainly.com/question/22361343

5 0
3 years ago
A student calculates the density of a copper cube to be 4.15 g/cm . If the accepted value is 8.64 g/cm the percentage error in h
Helen [10]

 The percentage error in his experimental value is -51.97%.

<h3>What is percentage error?</h3>

This is the ratio of the error to the actual measurement, expressed in percentage.

To calculate the percentage error of the student, we use the formula below.

Formula:

  • Error(%) = (calculated value-accepted value)100/(accepted............. Equation 1

From the question,

Given:

  • Calculated value = 4.15 g/cm
  • accepted value = 8.64 g/cm

Substitute these values into equation 1

  • Error(%) = (4.15-8.64)100/8.64
  • Error(%) = -4.49(100)/8.64
  • Error(%) = -449/8.64
  • Error(%) = -51.97 %

 

Hence, The percentage error in his experimental value is -51.97%.

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Covalent bond occurs due to chemical reaction
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4 years ago
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