Answer:
Yes, table
Yes, road
No
No, that would be a tension force
Yes, elevator floor
Yes, conveyor belt
Yes, force acts outward perpedicular to ramp surface
No
I'm going to assume this is over a horizontal distance. You know from Newton's Laws that F=ma --> a = F/m. You also know from your equations of linear motion that v^2=v0^2+2ad. Combining these two equations gives you v^2=v0^2+2(F/m)d. We can plug in the given values to get v^2=0^2+2(20/3)0.25. Solving for v we get v=1.82 m/s!
Explanation:
It is given that,
Radius of bowl, r = 3 m
A small block is released from rest from the edge of a large hemispherical friction less bowl. Let v is the speed of the mass when it passes through the bottom of the bowl and u is the initial speed of the mass, u = 0. Using conservation of energy as :

h = r = 3 m


v = 7.66 m/s
or
v = 7.7 m/s
So, the speed of the mass at the bottom of the bowl is 7.7 m/s. Hence, this is the required solution.
0J
According to the law of conservation of energy, the potential energy is converted to kinetic energy. Remember, potential energy is calculated using height and weight. If the ball is on the ground, height is 0.