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sergiy2304 [10]

3 years ago

5

Unpolarized light passes through three polarizing filters. The first one is oriented with a horizontal transmission axis, the se

cond filter has its transmission axis 31.8° from the horizontal, and the third one has a vertical transmission axis. What percent of the light gets through this combination of filters?

1 answer:

Xelga [282]3 years ago

4 0

Answer:

10.028%

Explanation:

$\theta$ = Angle between polarizer

The polarized light after passing through first polarizer

$I=\frac{I_0}{2}$

The polarized light after passing through second polarizer

$I_2=\frac{I_0}{2}cos^2\theta\\\Rightarrow I_2=\frac{I_0}{2}cos^231.8\\\Rightarrow I_2=0.36115I_0$

The polarized light after passing through third polarizer

$I_3=I_2cos^2(90-31.8)\\\Rightarrow I_3=0.36115I_0cos^2(90-31.8)\\\Rightarrow I_3=0.10028I_0$

$\frac{I_3}{I_0}\times 100=\frac{0.10028I_0}{I_0}\times 100\\ =10.028\ \%$

The percent of the light gets through this combination of filters is 10.028%

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Answer:

The maximum potential energy of the system is 0.2 J

Explanation:

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When the spring is stretched, it acquires potential energy. When released, the potential energy is converted into kinetic energy. If there is no friction nor any dissipative forces, all the potential energy will be converted into kinetic energy according to the energy conservation theorem.

The equation of elastic potential energy (EPE) is the following:

EPE = 1/2 · k · x²

Where:

k = spring constant.

x = stretching distance.

The elastic potential energy is maximum when the block has no kinetic energy, just before releasing it.

Then:

EPE = 1/2 · 40 N/m · (0.1 m)²

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3 years ago

In the Bohr model of the hydrogen atom, the speed of the electron is approximately 2.2 106 m/s.

Murrr4er [49]

The central force acting on the electron as it revolves in a circular orbit is $9.52 \times 10^{-8} \ N$ .

The given parameters;

<em>speed of electron, v = 2.2 x 10⁶ m/s</em>
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The central force acting on the electron as it revolves in a circular orbit is calculated as follows;

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where;

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Thus, the central force acting on the electron as it revolves in a circular orbit is $9.52 \times 10^{-8} \ N$ .

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Answer:

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To cross a river the swimmer swims relative to river in perpendicular direction.

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So

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Velocity of swimmer relative to ground = 3 i -5 j

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3 years ago

A 6.72 particle moves through a region of space where an electric field of magnitude 1270 N/C points in the positive direction,

Romashka [77]

Answer:

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Explanation:

Using:

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Force = magnitude of charge * velocity * magnetic field * sin tither

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Magnetic field is in the positive Z direction, net force is in the positive x direction.

According to right hand rule, Force acting on particle is perpendicular to the direction of magnetic field and velocity of particle. This would mean the force is along the y-axis. As this is a negatively charged particle, the direction of the velocity of the particle is reversed. Therefore velocity of particle, v, has to be in the negative y direction.

Now,

$F_{xnet}- F_{x1 } = F_{x2 }$

$(6.13*10^{-3}) - (8.53*10^{-3} ) = (7.728*10^{-6})*(v)$

$v = (F_{xnet} - F_{x1}) / (F_{x2} )$

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Answer:

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