Answer:
The no of revolutions rotor turn before coming to rest is 1,601.1943 and time taken is equal to 19.21 seconds
Explanation:
here we know that torque = I×α
α= angular acceleration
I = moment of inertia of hollow disc = m×
given that m=4.37kg
k=0.0710m
torque=1.2Nm
from the above equation we can calculate the angular acceleration of the hollow disc .
since
from this above equation
no of revolutions = = 1,601.1943.
Now to calculate time we know that time =
so upon calculating we will be getting t=19.21 seconds