To convert boiling water to steam, that would involve heat of vaporization. The heat of vaporization for water at atmospheric conditions is: ΔHvap = <span>2260 J/g.
Molar mass of water = 18 g/mol
Q = m</span>ΔHvap = (1.50 mol water)(18 g/mol)(<span>2260 J/g) = 61,020 J
Time = Q/Rate = (61,020 J)(1 s/20 J) = 3051 seconds
In order to express the answer in three significant units, let's convert that to minutes.
Time = 3051 s * 1min/30 s = <em>102 min</em></span>
Answer:
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Explanation:
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Answer:
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Answer:
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Answer:
1.0 mole
Explanation:
From the question given above, the following data were obtained:
Volume (V) = 5 L
Temperature (T) = 205 K
Pressure (P) = 340 KPa
Gas constant (R) = 8.31 KPa.L/Kmol
Number of mole (n) =?
Using the ideal gas equation, the number of mole of the gas in the container can be obtained as follow:
PV = nRT
340 × 5 = n × 8.31 × 205
1700 = n × 1703.55
Divide both side by 1703.55
n = 1700 / 1703.55
n = 1.0 mole
Thus, the number of mole of the gas in the container is 1.0 mole
