3 years ago

A 1000-watt microwave oven takes 90 seconds to heat a bowl of soup.How many joules if energy does it use?

Physics

1 answer:

vodomira [7]3 years ago

3 0

Answer:

1 joule is 1 watt second

Explanation

Here 1000 x 90 watt seconds 90000= 90000 joules.

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A car traveling at 26 m/s starts to decelerate steadily. It comes to a complete stop in 13 seconds. What is its acceleration?

Alenkasestr [34]

accn = - 26m/s divided by 13 secs

accn = 2m/s/s

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3 years ago

Which of the following has the fewest calence electrons?

dlinn [17]

Answer:

both magnesium and strontium have 2 valence electrons

Explanation:

potassium has 8 valence electrons, and nitrogen has 5.

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2 years ago

Stars form from clouds of gas and dust. As a protostar gravitationally contracts within its parent cloud, "conservation of angul

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Answer:

D) True. the protostar rotates more quickly.

Explanation:

If the system is isolated, the angular momentum must be retained.

Initial

L₀ = I w₀

Final

$L_{f}$ = $I_{f}$ $w_{f}$

L₀ = $L_{f}$

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$w_{f}$ = I / $I_{f}$ w₀

In general, the radius of the cloud decreases significantly to form the star, the moment of inertia must decrease, so the angular velocity must increase

Let's examine the answers

A) False. The opposite happens

B) False. Speed changes

C) False. For this there must be an external force, which does not exist

D) True. You agree with the above

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3 years ago

There is a 120 V circuit in a house that is a dedicated line for the dishwasher, meaning the dishwasher is the only resistor on

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Answer:

The answer is 6.67 Ohms

Explanation:

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3 years ago

Read 2 more answers

An exoplanet has three times the mass and one-fourth the radius of the Earth. Find the acceleration due to gravity on its surfac

Harlamova29_29 [7]

Answer:

b. 48.0 g.

Explanation:

Given;

mass of the exoplanet, $M_p = 3M_e$

radius of the exoplanet, $r_p = \frac{1}{4} r_e$

The acceleration due to gravity of the planet is calculated as;

$g_p = \frac{GM_p}{r_p^2} \\\\for \ Earth's \ surface\\\\g = \frac{GM_e}{r_e^2} \\\\G = \frac{gr_e^2}{M_e} = \frac{g_pr_p^2}{M_p} \\\\\frac{gr_e^2}{M_e} = \frac{g_p(\frac{r_e}{4}) ^2}{3M_e} \\\\\frac{gr_e^2}{M_e} = \frac{g_pr_e ^2}{16\times 3M_e} \\\\g = \frac{g_p}{48} \\\\g_p = 48 \ g$

Therefore, the correct option is b. 48.0 g

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2 years ago