Near Greenland in the northern hemisphere <span />
Answer:
The correct answer is B)
Explanation:
When a wheel rotates without sliding, the straight-line distance covered by the wheel's center-of-mass is exactly equal to the rotational distance covered by a point on the edge of the wheel. So given that the distances and times are same, the translational speed of the center of the wheel amounts to or becomes the same as the rotational speed of a point on the edge of the wheel.
The formula for calculating the velocity of a point on the edge of the wheel is given as
= 2π r / T
Where
π is Pi which mathematically is approximately 3.14159
T is period of time
Vr is Velocity of the point on the edge of the wheel
The answer is left in Meters/Seconds so we will work with our information as is given in the question.
Vr = (2 x 3.14159 x 1.94m)/2.26
Vr = 12.1893692/2.26
Vr = 5.39352619469
Which is approximately 5.39
Cheers!
Answer:
525 Bq
Explanation:
The decay rate is directly proportional to the amount of radioisotope, so we can use the half-life equation:
A = A₀ (½)^(t / T)
A is the final amount
A₀ is the initial amount,
t is the time,
T is the half life
A = (8400 Bq) (½)^(18.0 min / 4.50 min)
A = (8400 Bq) (½)^4
A = (8400 Bq) (1/16)
A = 525 Bq
The number of cans that would be considered lethal if 10g was lethal and there where 12oz in a can is 419 cans.
<h3>How to convert mass?</h3>
According to this question, caffeine concentration is 1.99 mg/oz.
1.99 milligrams can be converted to grams as follows:
1.99milligrams ÷ 1000 = 0.00199grams
This means that 0.00199grams per oz is the caffeine concentration.
If there were 12 oz in a can, then, 0.00199grams × 12 = 0.02388 grams in 1 can.
This means that if 10grams is considered lethal, 10grams ÷ 0.02388 grams = 419 cans would be lethal for consumption.
Therefore, the number of cans that would be considered lethal if 10g was lethal and there where 12oz in a can is 419 cans.
Learn more about conversion factor at: brainly.com/question/14479308
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Answer:
is the first confirmed terrestial planet to have been discovered outside the solar system by the kepler space telescope
Explanation: