Answer:
36.08%
Explanation:
We are given the overall formula of the compound as: CuSO4•5H2O
Now, atomic mass of the elements are;
Cu = 63.55 g/mol
S = 32.07 g/mol
O = 16 g/mol
H20 = 18.02 g/mol
Now, let's calculate the total mass of the compound:
(63.55 g/mol) + (32.07 g/mol) + 4(16 g/mol) + 5(18.02 g /mol) = 249.72 g/mol
From the above, water in the compound is 5(H20)
Thus, total water atomic mass = 5 × 18.02 = 90.1 g/mol
Thus, percentage of water = (atomic mass of water/total mass of compound) × 100%
Percentage of water = (90.1/249.72) × 100% = 36.08%
Initially, weigh the correct amount of 
calculated from the formula.
Number of moles =
As 1 mole of is given and molar mass of is 
, then
1 mole of = 
Mass of in g = 
Thus,
1 mole of = 58.44 g.
Now, the weighed amount of i.e. 58.44 g is added to a 1 liter container and then add small amount of water in the container to dissolve the salt. After that, fill the container with distilled water to the graduation mark or until the total volume reaches 1 liter.
Thus, option (c) is correct i.e. first put one mole of salt in the container then add the water with stirring till the total volume reaches 1 liter.
Field or discipline
hope it helped
We have the compound: KSCN, Potassium thiocyanate, in an aqueous solution.
The dissociated reaction of the salt:
KSCN (aq) => K+ + SCN-
It has 2 ions. One of them is the potassium ion, K+ (cation) and the other one is the thiocyanate ion, SCN- (anion).
Answer:
K+, the potassium ion
SCN-, the thiocyanate ion
According to Dalton's Law, in a mixture of non-reacting gasses, thetotal pressure<span> exerted is the sum of the </span>partial pressures<span> of the component gasses. In more complicated circumstances, equilibrium states come into effect, but fortunately for us, </span>oxygen<span> is non-reactive with </span>water vapor<span>.</span>
