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Pepsi [2]
3 years ago
8

Write the equation for the formation of a fluoride anion from a fluorine atom. If the electron affinity of the fluorine atom is

328 kJ/mol, what is q when 2.5 mol of fluoride anions are formed from fluorine atoms? How much energy is released when one F atom accepts an electron?
Chemistry
1 answer:
Finger [1]3 years ago
5 0

Answer:

Part A. F + e⁻ → F⁻

Part B. -820 kJ

Part C. -5.45x10⁻²² kJ

Explanation:

Part A

The fluoride anion is formed when fluorine accepts an electron:

F + e⁻ → F⁻

Part B

The electron affinity is the energy necessary for the atom to accept 1 electron, which is exothermic, so it's negative. The total energy q is the electron affinity multiplied by the number of moles:

q = -328 kJ/mol * 2.5 mol

q = -820 kJ

Part C

By the Avogadros' number

1 mol --------- 6.02x10²³ atoms

x --------- 1 atom

By a simple direct three rule:

x = 1.66x10⁻²⁴ mol

So, the energy for 1 atom is:

q = -328 kJ/mol * 1.66x10⁻²⁴ mol

q = -5.45x10⁻²² kJ

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In an electron dot diagram of propane (C3H8), how many double bonds are present?
NeX [460]

Answer:- none

Explanations:- For naming hydrocarbons we use the suffix -ane, -ene and -yne.

-ane is used when we have only single bonds between all carbons. -ene is used if there is any double bond between two carbons and the -yne is used if there is any triple bond between two carbons.

The given name of the compound is propane. It ends at -ane and so it's an alkane and must have single bonds between all the carbons it has. So, there are zero double bonds present in C_3H_8 .

This is also clear from the below lewis dot structure of the compound.


4 0
3 years ago
Read 2 more answers
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worty [1.4K]

Answer:

Nuclear fusion is a reaction in which two or more atomic nuclei are combined to form one or more different atomic nuclei and subatomic particles. The difference in mass between the reactants and products is manifested as either the release or the absorption of energy. 

Explanation: Read this and you might be able to figure it out for yourself ☺️☺️☺️

6 0
3 years ago
Consider the reaction at 500 ° C 500°C . N 2 ( g ) + 3 H 2 ( g ) − ⇀ ↽ − 2 NH 3 ( g ) K c = 0.061 N2(g)+3H2(g)↽−−⇀2NH3(g)Kc=0.06
Sav [38]

Answer:

Q = 0.061 = Kc

Explanation:

Step 1: Data given

Temperature = 500 °C

Kc=0.061

1.14 mol/L  N2

5.52 mol/L H2

3.42 mol/L NH3

Step 2: Calculate Q

Q=[products]/[reactants]=[NH3]²/ [N2][H2]³

If Qc=Kc then the reaction is at equilibrium.  

If Qc<Kc then the reaction will shift right to reach equilibrium.

If Qc>Kc then the reaction will shift left to reach equilibrium.  

Q = (3.42)² / (1.14 * 5.52³)

Q = 11.6964/191.744

Q = 0.061

Q = Kc the reaction is at equilibrium.  

4 0
3 years ago
Be sure to answer all parts.The combustion of a 40.0−g gaseous mixture of H2 and CH4 releases 3766 kJ of heat. Calculate the amo
Svetach [21]

Answer:H2=11.4g

CH4=28.6g

Explanation:The complete combustion of the two gases can be represented by a balanced reaction below

1. CH4 +2O2___CO2+2H2O

2.2H2+O2___2H2O

Combining the two we have CH4 +2H2+3O2___

CO2+4H2O

Since the mixture contains 40gof CH4 and 2, therefore 20g of CH4 and 8g of H2 combines.

Calculated from their molecular Mass i.e CH4 12+4×2)=20 and 2H2= 2×2×2=8g

Mass of CH4=20/28×40=28.6g

2H2=8/28×40=11.4g

7 0
3 years ago
What are some similarities between sublimation and deposition?
Korolek [52]
<span>Sublimation: the substance changes directly from a solid to a gas without going through the liquid phase. Deposition: the substance changes directly from a gas to a solid without going through the liquid phase.</span>
7 0
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