Are you doing a research on C5 burning?I am Zy from China.
It is because they increases linearly due to adding of 1 proton at each step.
When 0.5 moles of Zn react with 0.4 moles of HCL the limiting reactant will be HCL and excess reactant is Zn 0.3 moles excess and 0.2 moles Zn will be consumed in the reaction.
<h3>What is the limiting reactant in the given equation ?</h3>
STEP1- Write the balanced equation
Zn + 2HCL → ZnCl₂ + H₂
STEP2- calculate the moles according to the reaction
1mol of Zn requires → 2moles of HCL
0.5 moles of Zn requires→ 1mol of HCL
Given moles of HCL is 0.4
STEP3- Apply unitary method
0.5/x=1/0.4
0.5×0.4= x
0.2=x
STEP4- excess reagent left 0.5-0.2=0.3
Hence, the 0.3mole of excess Zn is left
Learn more about limiting reactions numericals.
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Answer:
The answer to your question is: 0.25 l
Explanation:
Data
P1 = 1 atm
V1 = 0.5 l
P2 =2 atm
V2 = ?
T = constant
Formula
V1P1 = V2P2
Clear V2 from the formula
V2 = V1P1/P2
Substitution
V2 = (0.5)(1)/2 substitution
= 0.25 l result
