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erastovalidia [21]
3 years ago
7

What is one way to test whether and unknown solution is acidic or basic

Chemistry
2 answers:
dimulka [17.4K]3 years ago
7 0

an acid is an ionic compound that produces positive hydrogen ions when dissolved in water and a bacis is an ionic compound that produces negative hydroxide ions when dissolved in water

miss Akunina [59]3 years ago
3 0

<u>Answer:</u> By using litmus paper.

<u>Explanation:</u>

Litmus paper is an indicator which helps us to determine the solution as acidic or basic. These are of two types: red litmus paper and Blue litmus paper.

Red litmus paper is resistant to Acidic solution but it changes its color to blue when dipped in basic solution.

Blue litmus paper is resistant to Basic solution but it changes its color to red when dipped in acidic solution.

Hence, we can use litmus paper to test whether the unknown solution is acidic or basic.

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Consider the formation of hcn by the reaction of nacn (sodium cyanide) with an acid such as h2so4 (sulfuric acid): 2nacn(s)+h2so
Artemon [7]

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Molar mass of NaCN = 49 g/mol

Therefore, the mass of NaCN is

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​29. A gas has a volume of 1.75 L at -23°C and 150.0 kPa.
arsen [322]

The answer for the following mention bellow.

  • <u><em>Therefore the final temperature of the gas is 260 k</em></u>

Explanation:

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To find:

Final temperature (T_{2})

We know;

According to the ideal gas equation;

P × V = n × R ×T

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P represents the pressure of the gas

V represents the volume of the gas

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R represents the universal gas  constant

T represents the temperature of the gas

We know;

\frac{P*V}{T} = constant

\frac{P_{1} }{P_{2} } × \frac{V_{1} }{V_{2} } = \frac{T_{1} }{T_{2} }

Where;

(P_{1}) represents the initial pressure of the gas

(P_{2}) represents the final pressure of the gas

(V_{1}) represents the initial volume of the gas

(V_{2}) represents the final volume of the gas

(T_{1}) represents the initial temperature of the gas

(T_{2}) represents the final temperature of the gas

So;

\frac{150 * 1.75}{210 * 1.30} = \frac{260}{T_{2} }

(T_{2}) =260 k

<u><em>Therefore the final temperature of the gas is 260 k</em></u>

<u><em></em></u>

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