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siniylev [52]
3 years ago
7

An instructor wishes to determine the wavelength of the light in a laser beam. To do so, she directs the beam toward a partition

with two tiny slits separated by 0.195 mm. An interference pattern appears on a screen that lies 4.85 m from the slit pair. The instructor's measurements show that two adjacent bright interference fringes lie 1.55 cm apart on the screen. What is the laser's wavelength (in nm)
Physics
1 answer:
Rus_ich [418]3 years ago
6 0

Answer:

λ = 623.2 nm

Explanation:

We are given;

separation distance; d = 0.195 mm = 0.195 × 10^(-3) m

interference pattern distance; D = 4.85 m

Width of two adjacent bright interference; w = 1.55 cm = 1.55 × 10^(-2) m

Formula for fringe width is given as;

w = λD/d

Where λ is wavelength

Thus;

λ = dw/D

λ = (0.195 × 10^(-3) × 1.55 × 10^(-2))/4.85

λ = 0.0000006232 m

Converting to nm gives;

λ = 623.2 nm

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Answer : The final pressure in the two containers is, 2.62 atm

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

Thus, the expression for final pressure in the two containers will be:

PV=P_1V_1+P_2V_2

P=\frac{P_1V_1+P_2V_2}{V}

where,

P_1 = pressure of N₂ gas = 4.45 atm

P_2 = pressure of Ar gas = 2.75 atm

V_1 = volume of N₂ gas = 3.00 L

V_2 = volume of Ar gas = 2.00 L

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V = final volume of gas = (4.45 + 2.75) L = 7.2 L

Now put all the given values in the above equation, we get:

P=\frac{(4.45atm)\times (3.00L)+(2.75atm)\times (2.00L)}{7.2L}

P=2.62atm

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