Answer: multiply (1/3√x-3/2√y)^2
Step-by-step explanation: Answer: 1/2 of 1/2 is 1/4.
Answer:the size of the button hole is 2.35 cm
Step-by-step explanation:
For a button to fit through its button-hole, the hole needs to be the size of the buttons diameter.
The formula for determining the circumference of a circle is expressed as
Circumference = πd or 2πr
Where
d represents the diameter of the circle
π is a constant given as 3.14
From the information given, the circumference of the button is 7.38 cm. Therefore, the diameter of the button will be
d = circumference/π = 7.38/3.14
d = 2.35 cm
Answer:
x = -2
y = -1
(-2, -1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
- Solving systems of equations by graphing
Step-by-step explanation:
<u>Step 1: Define systems</u>
y = x + 1
3x + 3y = -9
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 3x + 3(x + 1) = -9
- Distribute 3: 3x + 3x + 3 = -9
- Combine like terms: 6x + 3 = -9
- Isolate <em>x</em> term: 6x = -12
- Isolate <em>x</em>: x = -2
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = x + 1
- Substitute in <em>x</em>: y = -2 + 1
- Add: y = -1
<u>Step 4: Graph systems</u>
<em>Check the solution set.</em>
<h3>
Answer: -a > -b</h3>
Explanation:
Let's go over an example.
We'll have a = 1 and b = 7 which makes a < b true. Feel free to pick your own favorite pair of numbers such that b is larger than 'a'.
The corresponding opposites are: -a = -1 and -b = -7
The relationship flips because the opposites of each number are flipped. So instead of saying -a < -b, we have -a > -b
Sure enough, -1 > -7 is a true statement. Use a number line to see this. I recommend a vertical number line.
In short, going from a < b to -a > -b means we flip the signs of each term, and we flip the inequality sign as well.
Answer:
See below.
Step-by-step explanation:
So, we have:

Recall that secant is simply the reciprocal of cosine. So we can:

Now, recall the unit circle. Since cosine is negative, it must be in Quadrants II and/or III. The numerator is the square root of 3. The denominator is 2. The whole thing is negative. Therefore, this means that 150 or 5π/6 is a candidate. Therefore, due to reference angles, 180+30=210 or 7π/6 is also a candidate.
Therefore, the possible values for theta is
5π/6 +2nπ
and
7π/6 + 2nπ