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givi [52]
3 years ago
10

What do you think we call this graphical representation based on your prior experience with electric fields and electric field l

ines? Is this quantity (which you are observing though the compass's behavior) a vector or scalar? How do you know?
Physics
1 answer:
slavikrds [6]3 years ago
6 0

Answer:

Explanation:

The strengthcompassion field is proportional to the closeness of the field lines—more precisely, it is proportional to the number of lines per unit area perpendicular to the lines. The direction of the electric field is tangent to the field line at any point in space. Field lines can never cross. These pattern of lines, sometimes referred to as electric field lines, point in the direction that a positive test charge would accelerate if placed upon the line. As such, the lines are directed away from positively charged source charges and toward negatively charged source charges.

Rules for drawing electric field lines

1. Electric field lines are always drawn from High potential to

low potential.

2. Two electric field lines can never intersect each other.

3. The net electric field inside a Conductor is Zero.

4. Electric field line from a positive charge is drawn radially outwards and from a negative charge radially inwards.

5. The density of electric field lines tells the strength of the electric field at that region.

6. Electric field lines terminate Perpendicularly to the surface of a conductor.

A vector quantity has a direction and a magnitude, while a scalar has only a magnitude. You can tell if a quantity is a vector by whether or not it has a direction associated with it.

So, electric fields are vector quantity due to the fact any student can tell you that a compass is used to determine which direction is north.

Since the compass always point northward, then it has a direction and magnitude and so it is a vector quantity

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A group of physicists perform an experiment. The measurements that they took were carefully made but they failed to obtain the c
koban [17]

The group of physicists that failed to obtain the correct measurements failed in obtaining accuracy.

<h3>What is accuracy?</h3>

Accuracy is the state of being accurate; being free from mistakes, this exemption arising from carefulness; exactness; correctness.

Mathematically, accuracy is the exact conformity to truth, or to a rule or model or a degree of conformity of a measure to a true or standard value.

According to this question, a group of physicists perform an experiment. Although the measurements that they took were carefully made, they failed to obtain the correct measurements.

This suggests that the group of physicists failed in obtaining accuracy.

Learn more about accuracy at: brainly.com/question/13099041

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6 0
2 years ago
Consider a copper wire with a diameter of 0.450 mm. If you want to cut a piece of the wire so it has a resistance of 3.25 Ω, how
Arisa [49]

Answer:

30.7m

Explanation:

You can use the following equation:

ρ = R * \frac{S}{l}

Where ρ is the resistivity, R is the resistance, S is the Cross-sectional Area and l is the length of the wire.

We issolate l in the equation and solve with the data we have:

l = R * \frac{S}{p} = 3.25 Ω * \frac{0.25 *\pi * ((0.45/1000)^2}{1.68*10^-8}

l =  30.7m

5 0
3 years ago
When a physical change in a sample occurs, which of the following would NOT change?
GREYUIT [131]
It's Composition. (C)
3 0
3 years ago
A girl starts from rest and reaches a walking speed of 1.4 m/s in 3.0 s. She walks at this speed for 6.0 s. The girl then slows
Alona [7]

Answer:

1) The girl's acceleration at time 't' is, a=0.47 m/s²

2) The girl's acceleration at time 't₁' is, a_{1}=0 m/s²

3) The girl's acceleration at time 't₂' is,  a_{2}=-0.14 m/s²

Explanation:

Given data,

The initial walking speed of the girl, u = 0

The speed of the girl at the time 't' 3 s is, v₁ = 1.4 m/s

The time period the girl walked at the speed 1.4 m/s is, t₁ = 6 s

The girl slows down and comes to a stop during a period, t₂ = 10 s

1) The girl's acceleration at time 't'

                                a=\frac{v-u}{t}

                                a=\frac{1.4-0}{3}

                               a=0.47 m/s²

2) The girl's acceleration at time 't₁'

                                a_{1} =\frac{v_{1} -v}{t_{1}}

                                a_{1}=\frac{1.4-1.4}{6}

                               a_{1}=0 m/s²

3) The girl's acceleration at time 't₂'

                                a_{2} =\frac{v_{2} -v_{1}}{t_{2}}

                                a_{2}=\frac{0-1.4}{10}

                               a_{2}=-0.14 m/s²

4 0
3 years ago
A wheel has a radius of 9 centimeters and an axle radius of 3 centimeters. The IMA of the system is ___?
otez555 [7]

Answer:

Answer is C.

Explanation:

To calculate the IMA for a wheel and axle, find the ratio of the larger radius to the smaller radius:

IMA = R/r

IMA = 9/3

IMA = 3

4 0
4 years ago
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