Question

fuel was consumed at a certain rate of 0.05Kg\s in a rocket engine and ejected as a gas with a speed of4000m\s . Determine the thrust on the rocket​

Answer 1

Answer:

Thrust = 200 N

Explanation:

The engine thrust can be found by using the following formula:

$Thrust = mv$

where,

m = mass flow rate of the fuel = 0.05 kg/s

v = velocity of ejected gases = 4000 m/s

Therefore, using the given values in the equation, we get:

$Thrust = (0.05\ kg/s)(4000\ m/s)$

Thrust = 200 N