Answer: (C) 30 times
Richter scale is used to determine the magnitude of an earthquake from the arrival time of P and S waves. It determines the total amount of energy released during an earthquake.
If Richter magnitude scale measures 6.5 then it produces 30 times more energy than 1 Richter scale magnitude during an earthquake. The magnitude of an earthquake is plotted on a logarithmic scale from 1 to 9 and increases 10 folds by one magnitude. If 6.5 is the magnitude, it means it is 10 times more than 5.5 magnitude earthquake. Similarly the amount of energy is calculated as 30 folds. So 6.5 magnitude will have 30 folds more energy released than that with 5.5 magnitude earthquake.
Answer:
Blooms are alluring and show up in various hues and shapes to draw in pollinators who help in dust move. Most blooms have four primary parts: sepals, petals, stamens, and carpels. The stamens are the male part though the carpels are the female piece of the blossom.
Sepal: The outer parts of the flower (often green and leaf-like) that enclose a developing bud.
Petal: The parts of a flower that are often conspicuously colored.
Stamen: The pollen producing part of a flower, usually with a slender filament supporting the anther.
Anther: The part of the stamen where pollen is produced.
Pistil: The ovule producing part of a flower. The ovary often supports a long style, topped by a stigma. The mature ovary is a fruit, and the mature ovule is a seed.
Stigma: The part of the pistil where pollen germinates.
Ovary: The enlarged basal portion of the pistil where ovules are produced.
Receptacle: The part of a flower stalk where the parts of the flower are attached
Answer:
P4Se3
Explanation:
Applying the Law of Conservation of Mass:
(133 mg total) - (45.8 mg P) = 87.2 mg Se
Dividing by the molar mass,
Phosphorus:-(45.8 mg P) / (30.97376 g P/mol) = 1.4786 mmol P
Selenium:-(87.2 mg Se) / (78.96 g Se/mol) = 1.1044 mmol Se
Divide by the smaller number of millimoles:
(1.4786 mmol P) / 1.1044 mmol = 1.339
(1.1044 mmol Se) / 1.1044 mmol = 1.000
multiply by 3, to get a whole number interger. then round to the nearest whole numbers to find the empirical formula.
Therefore the empirical formula is P4Se3
The approximate partial pressure of oxygen at 1500 m is 0.18 atm.
<h3>Pressure of the air</h3>
From barometric pressure table;
1500 m = 85 kPa
1 kPa = 0.0099 atm
85 kPa = ?
= 0.84 atm
Oxygen percentage in air = 21%
<h3>Partial pressure of oxygen in air</h3>
P = 0.21 x P(total)
P = 0.21 x 0.84 atm
P = 0.18 atm
Thus, the approximate partial pressure of oxygen at 1500 m is 0.18 atm.
Learn more about partial pressure here: brainly.com/question/19813237
#SPJ11
Answer:
O2 is the limiting reactant.
Explanation:
Hello there!
In this case, according to the given information about this reaction, one could identify the limiting reactant by performing a mole ratio of H2S to SO2 and O2 to SO2:
![14.3molH_2S*\frac{2molSO_2}{2molH_2S}=14.3molSO_2 \\\\17.1molO_2*\frac{2molSO_2}{3molO_2}=11.4molSO_2](https://tex.z-dn.net/?f=14.3molH_2S%2A%5Cfrac%7B2molSO_2%7D%7B2molH_2S%7D%3D14.3molSO_2%20%5C%5C%5C%5C17.1molO_2%2A%5Cfrac%7B2molSO_2%7D%7B3molO_2%7D%3D11.4molSO_2)
Thus, since 17.1 moles of O2 yields fewer moles than 14.3 moles of H2S, we infer the former is the limiting reactant.
Regards!