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alukav5142 [94]
3 years ago
10

A gas cylinder contains 2.0 mol of gas X and 6.0 mol of gas Y at a total pressure of 2.1 atm. What is the partial pressure of ga

s Y? Use StartFraction P subscript A over P subscript T EndFraction equals StartFraction n subscript a over n subscript T EndFraction..
Chemistry
2 answers:
vivado [14]3 years ago
4 0

Answer :  The partial pressure of X and Y gases are, 0.525 and 1.575 atm respectively.

Explanation : Given,

Moles of X = 2.0 mole

Moles of Y = 6.0 mole

Total pressure = 2.1 atm

Now we have to calculate the mole fraction of X and Y.

\text{Mole fraction of }X=\frac{\text{Moles of }X}{\text{Moles of }X+\text{Moles of }Y}

\text{Mole fraction of }X=\frac{2.0}{2.0+6.0}=0.25

and,

\text{Mole fraction of }Y=\frac{\text{Moles of }Y}{\text{Moles of }X+\text{Moles of }Y}

\text{Mole fraction of }Y=\frac{6.0}{2.0+6.0}=0.75

Now we have to calculate the partial pressure of X and Y.

According to the Raoult's law,

p_i=X_i\times p_T

where,

p_i = partial pressure of gas

p_T = total pressure of gas  = 2.1 atm

X_i = mole fraction of gas

p_{X}=X_{(X)}\times p_T

p_{X}=0.25\times 2.1atm=0.525atm

and,

p_{Y}=X_{(Y)}\times p_T

p_{Y}=0.75\times 2.1atm=1.575atm

Thus, the partial pressure of X and Y gases are, 0.525 and 1.575 atm respectively.

storchak [24]3 years ago
3 0

Answer:

1.6 is the answer

Explanation:

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