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vovangra [49]
3 years ago
11

Which is not a way to accelerate an object?

Physics
1 answer:
GREYUIT [131]3 years ago
6 0
<span>Slowing an object down is not a means of accelerating it. It actually decelerates the motion of an object. Speeding it up, changing its direction and applying balanced forces accelerate an object. In order for an object to accelerate, a force must be applied. It follows Newton’s second law of motion where it states that a body at rest remains at rest unless a force is acted upon it. When you move an object, you are exerting a force onto it. By exerting a force on the object, you are actually displacing it from its initial position. You cannot apply force to the object without altering its position. Keep in mind that when you exert work, you are exerting energy too. </span>
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A green light is submerged 2.70 m beneath the surface of a liquid with an index of refraction 1.31. What is the radius of the ci
Anettt [7]

Answer:

The radius is  r = 3.1905 \ m

Explanation:

From the question we are told that

        The  distance  beneath the liquid  is  d =  2.70 \ m

        The refractive index of the liquid is  n_i  =  1.31

Now the critical value is mathematically represented as

         \theta =  sin ^{-1} [\frac{1}{n_i} ]

substituting values

         \theta =  sin ^{-1} [\frac{1}{131} ]

         \theta  =  49.76^o

Using SOHCAHTOA rule we have that

         tan \theta =  \frac{ r}{d}

=>     r =  d * tan \theta

substituting values  

        r =  2.7 * tan (49.76)

        r = 3.1905 \ m

         

5 0
3 years ago
A charged particle is moving in a uniform magnetic field at a speed of 8.2Ã10^3 m/s in a direction 87° from the direction of th
77julia77 [94]

Answer:

Magnetic field, B = 0.042 T

Explanation:

It is given that,

Speed of charged particle, v=8.2\times 10^3\ m/s

Angle between velocity and the magnetic field, \theta=87

Charge, q=5.7\ \mu C=5.7\times 10^{-6}\ C

Magnetic force, F = 0.002 N

The magnetic force is given by :

F=qvB\ sin\theta

B is the magnetic field  

B=\dfrac{F}{qv\ sin\theta}

B=\dfrac{0.002}{5.7\times 10^{-6}\times 8.2\times 10^3\times sin(87)}

B = 0.042 T

So, the strength of the magnetic field is 0.042 Tesla. Hence, this is the required solution.

5 0
3 years ago
THE ELECTROMAGNET SPECTRUM ONLY HAS WHICH SHAPE OF WAVE?
brilliants [131]

Answer: Transverse

Explanation: Transverse waves possess a vertical wave motion and a horizontal particle motion.

4 0
2 years ago
State the Newton 2nd law of motion and also prove that F= ma<br>​
saw5 [17]

Explanation:

F = ma is the formula of Newton's Second Law of Motion. Newton's Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.

...

3 0
3 years ago
Suppose that you measure a galaxy's redshift, and from the redshift you determine that its recession velocity is 30,000 (3×10^4)
anyanavicka [17]

Answer:

1.4 billion light years away

Explanation:

v = Recessional velocity = 30000 km/s[/tex]

H_0 = Hubble constant = \frac{65}{3.2\times 10^6}\ ly

D = Distance to the galaxy

According to Hubble's law

v=H_0D\\\Rightarrow D=\frac{v}{H_0}\\\Rightarrow D=\frac{3\times 10^{4}}{65}\times 3.2\times 10^6\\\Rightarrow D=1476923076.92307\ ly\\\Rightarrow D=1.4\times 10^9\ ly

The galaxy is 1.4 billion light years away

5 0
3 years ago
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